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Yuri [45]
3 years ago
5

Find the possible dimensions of the picture above please

Mathematics
1 answer:
Svetlanka [38]3 years ago
4 0

Answer:

(2x – 7) × (2x + 7)

Step-by-step explanation:

From the question given above, the following data were obtained:

Area (A) = (4x² – 49) m²

Dimension =?

The picture in the question above has a rectangular shape. Thus, the area is given by:

Area (A) = Length (L) × Width (W)

A = L × W

The dimension of the shape will be:

L × W

Now, we shall determine the dimension (L × W) as follow:

Area (A) = (4x² – 49) m²

Dimension (L × W) =?

A = L × W

L × W = 4x² – 49

Recall:

4 = 2²

49 = 7²

Thus,

L × W = 2²x² – 7²

L × W = (2x)² – 7²

Different of two squares

L × W = (2x – 7)(2x + 7)

L × W = (2x – 7) × (2x + 7)

Dimension = (2x – 7) × (2x + 7)

Therefore, the possible dimension (L × W) of the shape is (2x – 7) × (2x + 7)

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stepladder [879]
Hello there!

The correct answer is option B


2x² + (4x - 6x²) + 9 - (6x + 3)

Just take them out of the parentheses

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Combine like terms

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