Question: Is the pre-synaptic or the post-synaptic neuron damaged? Explain your rationale in detail (in other words, detail how you came to your conclusion). You're going to have to really think on this one. It's not something you can look up in the text. You will need to use what you have learned about the autonomic nervous system and some critical thinking to arrive at the answer.
Horner's Syndrome riddle: Ach is the neurotransmitter at all ANS preganglionic fibers, including SNS. The pt has decreased sweating and pupil constriction, indicating blockage of SNS transmission. When the MD gave ACh it induced sweating, but not pupil dilation. This is because the sweat glands are an exception in normal SNS transmission, as the postganglionic fibers utilize ACh as their neurotransmitters. Other SNS pathways utilize NE as their neurotransmitter. So ACh acted directly on the sweat gland to produce sweating, but could not stimulate the typical postsynaptic neurons to release NE. When the MD gave NE he saw pupil dilation, but not sweating, indicating the NE worked directly at the iris to produce pupil dilation. This indicaates the problem was with the postsganglionic neuron. If the preganglionic neuron were the problem injecting ACh would have solved both problems.
Are there options, or is it short answer?
<span>The two populations of donkeys will remain physically identical in both areas.</span>
Answer:
Excitement
Explanation:
Sympathetic nervous system is a type of autonomic nervous system that acts as an emergency system of the body.
Sympathetic nervous system prepares the body during fight and flight response. The energy is put out in this system and protects the body from the injury. During excitement the heart speeds up, blood pressure increases and more energy is available to the body. Hence, excitement is the characteristic of sympathetic division of nervous system.
Thus, the correct answer is option (b).
Answer:
1/4
Explanation:
1-Mother:
The probability to pass the disorder to her progeny is: 1 x 1/2 = 1/2
Father:
2-The probability to pass the disorder to his progeny is: 1 x 1/2 = 1/2
Therefore, the probability to have the disorder is equal to the product of both independent events, i.e., 1/2 x 1/2 = 1/4 or 25%
