Answer:
$ 2263
Step-by-step explanation:
In this case to calculate the standard error of the mean, we only need the standard deviation (sd) and the number of the random sample (n).
sd = 13000
n = 33
SE = sd / (n ^ (1/2))
replacing:
SE = 13000 / (33 ^ (1/2))
SE = 2263.01
What the standard error of the mean for a random sample of 33 first-year lawyers means is $ 2263
Answer:
125/12
Step-by-step explanation:
1st problem-no
2nd problem-yes
3rd problem-yes
4th problem-no
Solution :
Given :
Sample mean, 
Sample size, n = 129
Sample standard deviation, s = 8.2
a. Since the population standard deviation is unknown, therefore, we use the t-distribution.
b. Now for 95% confidence level,
α = 0.05, α/2 = 0.025
From the t tables, T.INV.2T(α, degree of freedom), we find the t value as
t =T.INV.2T(0.05, 128) = 2.34
Taking the positive value of t, we get
Confidence interval is ,
(32.52, 35.8)
95% confidence interval is (32.52, 35.8)
So with 
confidence of the population of the mean number of the pounds per person per week is between 32.52 pounds and 35.8 pounds.
c. About of confidence intervals which contains the true population of mean number of the pounds of the trash that is generated per person per week and about 
that doe not contain the true population of mean number of the pounds of trashes generated by per person per week.
Answer:
The correct answer is B
Step-by-step explanation:
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