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2 years ago

How does the digit in the ten thousands place compare to the digit in the thousands place

1 answer:

4 0

A digit in the ten thousand place has a value of 10,000 times the value of the mere digit. While a digit in the thousands place has a value 1,000 times the value of the digit. So to compare you can do 10,000 / 1,000 = 10, which means that a digit in the ten thousand place values ten times what the same digit values is it is the thousand place.

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Find the domain and range of 1/t+2

kotegsom [21]

Answer:

Domain = (-∞, -2) ∪ (-2, ∞).

Range = (-∞, 0) ∪ (0, ∞).

Step-by-step explanation:

t can't have the value -2 because that would make 1/(t + 2) = 1/0 which is undefined.

So the domain is All real values of t. except t = -2.

As t approaches infinity or negative infinity f(t) approaches zero, and as t approaches -2 from below or above f(t) approaches negative infinity or positive infinity.

8 0

3 years ago

Exercise I: Fruit ninja 1. Determine the surface S given by the equation x 2 − 4x + y 2 − 2y + z 2 − 6z = 2. 2. Find an equation

nalin [4]

Answer:

Step-by-step explanation:

Detailed solution on the attached pictures

6 0

3 years ago

At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o

bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, $P_0=15$

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

$P(x)=P_0(1+r)^x$

now, we can plug values

$P(x)=15(1+0.4142)^x$

$P(x)=15(1.4142)^x$

Average rate of change between 2 years and 4 years:

we can use formula

$A_1=\frac{P(4)-P(2)}{4-2}$

now, we can plug values

$A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}$

$A_1=14.99914$

Average rate of change between 4 years and 6 years:

we can use formula

$A_2=\frac{P(6)-P(4)}{6-4}$

now, we can plug values

$A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}$

$A_2=29.99770$

Average rate of change between 6 years and 8 years:

we can use formula

$A_3=\frac{P(8)-P(6)}{8-6}$

now, we can plug values

$A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}$

$A_3=59.99425$

now, we will check each options

option-A:

we can see that

$A_3-A_2=30$

So, this is FALSE

option-B:

$A_1=\frac{1}{2}A_2$

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

$A_1=\frac{1}{2}A_2$

so, this is FALSE

5 0

3 years ago

60 more points i believe

kondor19780726 [428]

f(x) does have an inverse function since it does pass the horizontal line test

5 0

2 years ago

Solve the system of equations by elimination. 2x+8y=10 -4x-9y=-13 x = y =

Reptile [31]

So use cancelation
multiply first equation by 2
2x+8y=10
times 2
4x+16y=20
now add

4x+16y=20
-4x-9y=-13 +
0x+7y=7
7y=7
divide by 7
y=1

subsittue

2x+8y=10
2x+8(1)=10
2x+8=10
subtract 8 from both sides
2x=2
divide by 2
x=1

x=1
y=1

8 0

3 years ago