Answer:
A) A = X^2 + 11X + 24
B) X = 18 ft
C) 414 ft^2
D) 132 ft^2
Step-by-step explanation:
A) Width W of yard and path = X + 3
Lenght L of path = X + 5 + 3 = X + 8 ft, therefore,
Area of yard and path = L x W = (X +3) x (X +8)
A = X^2 + 11X + 24
B) if area of the yard and path is 546 ft^2,
546 = X^2 + 11X + 24
X^2 +115X - 522 = 0 (quadratic equation)
Solving the quadratic equation gives
X = 18 and X = -29
Our answer can only be positive so we choose X = 18 ft
C) lenght of yard = 5 + 18 = 23 ft
Width = 18 ft
Therefore area = L x W = 23 x 18 = 414 ft^2
D) area of path = area of path and yard minus area of yard
= 546 - 414 = 132 ft^2
Answer:
39
Step-by-step explanation:
ur welcome
Y=x+12
(-4,8)
(10,22)
y=4x
(5,20)
(-4,-16)
(0,0)
<h3>
Answer: Choice B 
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Work Shown:
Angle theta is between 0 and pi/2, so this angle is in quadrant Q1.
Square both sides of the given equation
Then use the pythagorean trig identity to get
Answer:
x could be -7.089, 0.334, and 6.755.
Step-by-step explanation:
I graph the equation to find the solutions for x.
