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GrogVix [38]
3 years ago
5

What is the value of the interquartile range of the data below? A box-and-whisker plot. The number line goes from 0 to 52. The w

hiskers range from 10 to 51, and the box ranges from 29 to 41. A line divides the box at 32.
Mathematics
2 answers:
Softa [21]3 years ago
5 0

Answer:

The interquartile range is 12.

Step-by-step explanation:

In a box-and-whisker plot, the left edge of the box is the lower quartile and the right edge of the box is the upper quartile. The line dividing the box is the median. The end of the left whisker shows the minimum value. The end of the right whisker shows the maximum value.

In your question, the lower quartile is 29, the upper quartile is 41, while the median is 32. The minimum value is 10 and the maximum value is 51.

The formula for the interquartile range is as follows:

Interquartile Range = Upper quartile - Lower quartile

In this question, interquartile range = 41 - 29 which equals 12. Hence, the answer is 12.  

Ainat [17]3 years ago
3 0

Answer:

12

Step-by-step explanation:

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Which of the relations given by the following sets of ordered pairs is a function?
adell [148]
Functions cannot have the same X value (the first number), but they can have the same Y value (the second number).
<span>A. {(1,2),(2,3),(3,4),(2,1),(1,0)}
B. {(2,−8),(6,4),(−3,9),(2,0),(−5,3)}
C. {(1,−3),(1,−1),(1,1),(1,3),(1,5)}
D. {(−2,5),(7,5),(−4,0),(3,1),(0,−6)}

Choice A. has two repeating X values [(1,2) and (1,0), (2,3) and (2,1)]
Choice B. has one repeating X value [(2, -8) and (2,0)]
Choice C. all has a repeating X value (1)
Choice D doesn't have any repeating X values.

In short, your answer would be choice D [</span><span>{(−2,5),(7,5),(−4,0),(3,1),(0,−6)}] because it does not have any repeating X values.</span>
8 0
4 years ago
Round the number below to the thousands place 2,181,465
grigory [225]
Rounding off to thousandths is referring to the hundredth number(3rd number from right)

if it's >5, it +1 to the thousand's number (4th number from right),
eg. 4570 rounded off by thousand = 5000 

if <5 then it reduces to 0.
eg. 3489 rounded off by thousand = 3000

for your case, 2,181,465 rounded off to thousand = 2,181,000


7 0
3 years ago
5 Vera is a shop manager. 5 She has this information about the income in her shop for eight weeks this year. Week 1 2. 3 4 5 6 7
Alex

Using the median concept, it is found that it suffered a 11.16% decrease.

<h3>What is the median of a data-set?</h3>

It is the 50th percentile of the data-set, which is the value that separates the lower 50% from the upper 50%.

In this problem, the ordered data-set, in thousands of £, is given by:

{19.4, 39.8, 42.3, 42.5, 45.1, 47.9, 52.4, 53.5}

It has even cardinality, hence the median is the mean of the 8/2 = 4th and 5th terms, so:

M = (42.5 + 45.1)/2 = £43800.

It decreased from £49300 last year. The percentage decrease is the change divided by initial amount and multiplied by 100%, hence:

P = (49300 - 43800)/49300 x 100% = 11.16%.

More can be learned about the median concept at brainly.com/question/25215461

5 0
2 years ago
A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int
Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}

By expanding the previous equation:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0

Since there is no accumulation within the tank, expression is simplified to this:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}, where c(0) = 0 \frac{pounds}{gallon}.

\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}

The solution of this equation is:

c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})

The salt concentration after 8 minutes is:

c(8) = 0.166 \frac{pounds}{gallon}

The instantaneous amount of salt in the tank is:

m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds

3 0
3 years ago
The measure of one angle is 130 which statement is true regarding the 130 angle and angle 3
Dafna11 [192]
According to Figure that is shown below, the correct answer for this problem is:

<span>B. They are alternate interior angles, so angle 3 also measures 130°. 

</span>The same happens with 7 and 11. This is an obtuse angle, that is, this kind of angles measures more than 90° but less than 180°. 

7 0
3 years ago
Read 2 more answers
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