The question is simple and the explanation but I will give you
Answer:
A and B is correct ...............
Answer:
Option (B)
Step-by-step explanation:
From the graph attached,
Vertical asymptotes of the function are x = -2, 5
Horizontal asymptote is y = 0
Now we take each option,
Option (A),
F(x) =
No horizontal asymptote
Vertical asymptote : x = -2
Option (B),
F(x) =
Horizontal asymptotes : y = 0
Vertical asymptotes : x = 5, -2
Option (C),
F(x) =
Vertical asymptote : x = 0
No horizontal asymptote.
Therefore, Function given in Option (B) matches the asymptotes given in the graph.
Option (B) represents the graph.
g(x) = -x² + 10x - 30
the equation of a quadratic in vertex form is
y = a(x - h)² + k
where (h, k ) are the coordinates of the vertex and a is a multiplier
here vertex = (5, - 5 ), hence
y = a(x - 5)² - 5
to find a substitute the point on the graph (8, - 14) into the equation
- 14 = 9a - 5 ⇒ 9a = - 9 ⇒ a = - 1
y = - (x - 5)² - 5 = - (x² - 10x + 25) - 5 = - x² + 10x - 30
g(x) = - x² + 10x - 30 ← in standard form