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Marizza181 [45]
2 years ago
12

A charge of 6.4 × 10–7 C experiences an electric force of 1.8 × 10–1 N. What is the electric field strength?

Mathematics
1 answer:
MrMuchimi2 years ago
6 0

Answer:

60 hemos soy mexicano espero que te sirva

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F(x) = 1/(5x-6)Find the derivative of this function
siniylev [52]

Given

f(x)=\frac{1}{5x-6}

To find the derivative of the give function,we apply below exponent rule first:

\frac{1}{a}=a^{-1}

So,

Next, we apply the chain rule:

So,

We substitute back u=(5x-6):

Simplify:

Therefore, the answer is:

=-\frac{5}{(5x-6)^2}

5 0
11 months ago
Leonard and Liam each own a collection of vintage cars. Leonard has 7 cars more than Liam has. Three times the number of cars Le
dimulka [17.4K]

Answer: The answer is (22, 15).

Step-by-step explanation:  Given that 'x' represents the number of cars Leonard has and 'y' represents the number of cars Liam has.

Then, according to the given information, we have

x-y=7,\\\\3x+2y=96.

Multiplying the first equation by 2 and adding to the second equation, we have

2x+3x=14+96\\\\\Rightarrow 5x=110\\\\\Rightarrow x=22.

So,

y=x-7=22-7=15.

Therefore, Leonard has 22 cars and Liam has 15 cars.

Thus, (22, 15) is the solution to the given system.

5 0
3 years ago
Read 2 more answers
What is an equation of the line that passes through the point (−5,−1) and is parallel to the line 4x+5y=45?
frozen [14]

This gives you, 4x + 5y = -25 as your final answer.
8 0
2 years ago
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Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays
katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

<u>Answer:</u> The half life of the sample of phosphorus-32 is 14.28days^{-1}

<u>Step-by-step explanation:</u>

The equation used to calculate the half life of the sample is given as:

m(t)=m_o(1/2)^{t/h}

where,

m(t) =  amount of sample after time 't' = 356 g

m_o = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}

Hence, the half life of the sample of phosphorus-32 is 14.28days^{-1}

7 0
3 years ago
If you work for an hourly wage, your gross pay is a function of the number of hours that you work. Your hourly wage is $8.50 per
ziro4ka [17]
Your answer would be A because gross pay= 8.50$ times the number of hours you work.

6 0
3 years ago
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