Answer:
- h(x) = -2x^2 -x +3
- Reservoir A releases the same amount of water as Reservoir B over 1 week
Step-by-step explanation:
<u>Given</u>:
f(x) = x^2 -7x +5
g(x) = 3x^2 -6x +2
h(x) = f(x) -g(x)
<u>Find</u>:
h(x)
h(1)
<u>Solution</u>:
The expression for h(x) is found by evaluating its definition:
h(x) = (x^2 -7x +5) -(3x^2 -6x +2)
h(x) = x^2(1 -3) +x(-7 -(-6)) +(5 -2)
h(x) = -2x^2 -x +3
Then h(1) is found by substituting 1 for x:
h(1) = -2(1^2) -(1) +3 = -2 -1 +3
h(1) = 0 . . . . difference in release amounts after 1 week is 0
The true statements are ...
- h(x) = -2x^2 -x +3
- Reservoir A releases the same amount of water as Reservoir B over 1 week
59 that the anaqueles y un poco del aire
Answer:
y=-1/5x+6
Step-by-step explanation:
y-b=m(x-a)
×5) y-7=-1/5(x--5) (×5
5y-35=-1(x+5)
5y-35=-x-5
5y=-x+30
y=-1/5x+6
Answer:
LOL CAUGHT U LACKIN ON THAT DFA
Step-by-step explanation:
J+(2J-3)=30
3J-3=30
3J=33
J=11
Her brother is (2J-3) so 19
19+11=30
