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madreJ [45]
3 years ago
8

Round 53.17 to the nearest tenth. A) 50.0 B) 53.1 C) 53.2 D) 60.0

Mathematics
1 answer:
Alex777 [14]3 years ago
5 0
The answer is 53.2. anything greater than 5 rounds up
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Find the greatest common factor of the following monomials 38n3 8n4
mezya [45]
38n^{3}=2*19*n*n*n\\8n^{4}=2*2*2*n*n*n*n\\\\GCF=2*n*n*n=2n^{3}
8 0
3 years ago
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Solve the equation -4 + 4a = 12 for a.
WARRIOR [948]

Hello there! The answer to your question is a = 4.

To solve for a in the equation -4 + 4a = 12 you want to isolate, or separate, a from all of the equation's other values.

Our first step is to add 4 to both sides so the 4 cancels out on the left side.

-4+4 + 4a = 12+4

4a = 16

Next, we divide both sides by 4 to finish isolating a.

4/4a = 16/4

a = 4

Want to verify that this is correct? Place the value we found for a (4) into the equation in place of a and if it comes out as a true statement, the answer is correct.

-4 + 4(4) = 12

-4 + 16 = 12

12 = 12

Since 12 is in fact equal to 12, i can guarantee you that i have provided you with the correct answer. I hope this helps & have a great rest of your day! :)

6 0
3 years ago
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A number k plus 19.5 is less than or equal to 40
Yuri [45]
K+19.5≤ 40
You can then proceed to solve the inequality
3 0
3 years ago
Please help me with this
aliya0001 [1]

Hey!

--------------------------------------------------------

a. Has a vertical axis of symmetry.

Answers: B and D

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b. Has a horizontal axis of symmetry.

Answers: D and E

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c. Passes through exactly one quadrant.

Answers: A and D

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d. Passes through all 4 quadrants.

Answers: B and F

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Hope This Helped! Good Luck!

7 0
3 years ago
What property is illustrated by the equation 5+-5=0
Likurg_2 [28]
<span>The Correct Answer is

Associative Property of Multiplication (Numbers)    </span>6 • (3 • 2) = (6 • 3) • 2<span>
<span>
Additive Identity (Numbers)    </span></span>6 + 0 = 6
<span>
Additive Inverse (Numbers)    </span>5 + (-5) = 0
<span>
Multiplicative Identity (Numbers)   </span>5 • 1 = 5<span> 
  </span>
4 0
3 years ago
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