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larisa [96]
4 years ago
14

The point (8,-4) lies on a circle. What is the length of the radius of this circle if the center is located at (5,-7)

Mathematics
1 answer:
Kamila [148]4 years ago
4 0
Notice the picture, the radius is just the distance from the
center to a point on the circle, thus

\bf \textit{distance between 2 points}\\ \quad \\\\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{5}}\quad ,&{{ -7}})\quad 
%  (c,d)
&({{ 8}}\quad ,&{{ -4}})
\end{array}\qquad 
%  distance value
\\\\\\
\begin{array}{llll}
d = &\sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\
&\qquad \uparrow \\
&radius
\end{array}

\bf \begin{array}{llll}
d = &\sqrt{({{ 8}}-{{ 5}})^2 + ({{ -4}}-{{(-7)}})^2}\\
&\qquad \uparrow \\
&radius
\end{array}
\\\\\\
d=\sqrt{(3)^2+(-4+7)^2}\implies d=\sqrt{3^2+3^2}\implies d=\sqrt{18}
\\\\\\
d=\sqrt{9\cdot 2}\implies d=\sqrt{3^2\cdot 2}\implies d=3\sqrt{2}



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Step-by-step explanation:

SAMDEB

1. Subtract 7 from both sides.     6T + 7 - 7 = 61 - 7

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3 years ago
A study is done to determine if students in the California state university system (sample 1) take longer to graduate, on averag
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Answer:

We conclude that the students in the California state university system take longer to graduate as compared to students enrolled in private universities.

Step-by-step explanation:

We are given that from years of research, it is known that the population standard deviations are 1.5 years and 0.9 years, respectively.

One hundred students from each the California state university system and private universities are surveyed. The California state university system students took on average 4.8 years while the private university students took on average 4.4 years.

<em>Let </em>\mu_1<em> = population average time taken by students in the California state university system to graduate</em>

<em>      </em>\mu_2 = <em>population average time taken by students in the private universities to graduate</em>

SO, <u>Null Hypothesis</u>, H_0 : \mu_1-\mu_2\leq0  or  \mu_1 \leq \mu_2   {means that the students in the California state university system take less than or equal time to graduate as compared to students enrolled in private universities}

<u>Alternate Hypothesis</u>, H_A : \mu_1-\mu_2 >0  or  \mu_1>\mu_2   {means that the students in the California state university system take longer to graduate as compared to students enrolled in private universities}

The test statistics that will be used here is <u>Two-sample z test</u> <u>statistics</u> as we know about the population standard deviations;

                         T.S.  = \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{\sqrt{\frac{\sigma_1^{2} }{n_1} + \frac{\sigma_2^{2} }{n_2}} }  ~ N(0,1)

where,  \bar X_1 = sample average time taken by the California state university system students to graduate = 4.8 years

\bar X_2 = sample average time taken by the private university students to graduate = 4.4 years

\sigma_1 = population standard deviation for California state university system students = 1.5 years

\sigma_2 = population standard deviation for private university students = 0.9 years

n_1 = sample of California state university system students taken = 100

n_2 = sample of private university students taken = 100

So, <em><u>test statistics</u></em>  =   \frac{(4.8-4.4)-(0)}{\sqrt{\frac{1.5^{2} }{100} + \frac{0.9^{2} }{100}} }

                               =  2.287

<em>Now at 0.10 significance level, the z table gives critical value of 1.2816 for right-tailed test. Since our test statistics is more than the critical value of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.</em>

Therefore, we conclude that the students in the California state university system take longer to graduate as compared to students enrolled in private universities.

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Hope it helps! :)
3 0
3 years ago
Read 2 more answers
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