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Zielflug [23.3K]
3 years ago
7

Solve for x: negative 3 over 2, multiplied by x minus 9 equals negative 27 −24 −12 11 12 Btw please show the work bc i not only

want the answer, i also want to understand it too
Mathematics
2 answers:
Alexxandr [17]3 years ago
7 0
The answer is -24. First, add 9 to both sides to cancel it out; you get negative 3 over 2 equals 36. Then, you multiply both sides by negative 2 over 3 to cancel out the fraction and you get -24.
Firdavs [7]3 years ago
6 0

Answer:

\boxed{ x = 12}

Step-by-step explanation:

<u>Given Equation is:</u>

\frac{-3}{2} (x) - 9 = -27

Adding 9 to both sides

=> \frac{-3x}{2} = -27+9

=> \frac{-3x}{2} = -18

Multiplying 2 to both sides

=> -3x = -18 * 2

=> -3x = -36

Dividing both sides by -3

=> x = 12

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The equation A=1250(1.03)^7 is being used to calculate the amount of money in a savings account. What does the 1.03 represent in
Lelechka [254]

Answer:

The amount of Interest

Step-by-step explanation:

I'm 98% sure. It make sense because that how much interest ^7 you would multiply by 1250. And I've had questions like this. Hope this helps!

8 0
3 years ago
How many 3 3/4 inch wires can be cut from a spool if wire that is 100 inches how much will be left over
Akimi4 [234]

How many 3\frac{3}{4} wires can be cut from a spool of wire that is 100 inches long?

How many inches will be left over?

Number of pieces of wires = length of spool of wire ÷ length of each piece of wire.

Number of pieces = 100 ÷ 3\frac{3}{4} = 100 ÷ \frac{15}{4}

That gives \frac{100 * 4}{15}

Simplifying gives \frac{400}{15} = \frac{80}{3}

This is equivalent to 26\frac{2}{3} pieces

So 26 pieces of wires can be cut from a spool and \frac{2}{3} of a piece will be left over.

6 0
3 years ago
A woman has 21 total coins in her pocket, all of which are either dimes or quarters. If the total value of her change is $3.90,
Elza [17]

Answer with Step-by-step explanation:

Let there be d dimes and q quarters

A woman has 21 total coins in her pocket.

⇒ d+q=21    ------(1)

1 dime=$ 0.1

1 quarter=$ 0.25

The total value of her change is $3.90

⇒ 0.1d+0.25q=3.90

Multiplying both sides by 100,we get

10d+25q=390     --------(2)

(2)-10×(1)

10d+25q-10d-10q=390-210

15q=180

Dividing both sides by 15, we get

q=12

Putting value of q in (1),we get

d=9

Hence, Number of dimes=9

and number of quarters=12

Write the number of dimes, then the number of quarters separated by a comma.

9,12

8 0
3 years ago
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Solve the problem. Round as appropriate.
Monica [59]

Answer:

i need the points

Step-by-step explanation:

8 0
3 years ago
Jamie has a collection of 78 nickels, dimes, and quarters worth $12.40. If the number of quarters is
fgiga [73]

Jamie has 25 nickels, 14 dimes and 39 quarters in his collection

Step-by-step explanation:

The given is:

1. Jamie has a collection of 78 nickels, dimes, and quarters

2. They worth $12.40

3. If the number of quarters is  doubled, the value becomes $22.15

Assume that there are n nickels, d dimes and q quarters

∵ The collection of Jamie has 78 coins

∴ n + d + q = 78 ⇒ (1)

∵ 1 nickels = 5 cents

∵ 1 dimes = 10 cents

∵ 1 quarter = 25 cents

∵ The collection of Jamie worth $12.40

- Change the value of the collection to cents

∵ $1 = 100 cents

∴ The collection of Jamie worth = 12.40 × 100 = 1240 cents

∴ 5n + 10d + 25q = 1240

- Divide all terms by 5 to simplify it

∴ n + 2d + 5q = 248 ⇒ (2)

∵ When the number of quarters is  doubled, the value becomes

   $22.15

∵ The number of quarters is q

∴ The new number of quarters is 2q

∵ The value of coins is $22.15

∵ $22.15 = 22.15 × 100 = 2215 cents

∴ 5n + 10d + 25(2q) = 2215

∴ 5n + 10d + 50q = 2215

- Divide each term by 5 to simplify it

∴ n + 2 d + 10q = 443 ⇒ (3)

Subtract equation (2) from equation (3)

∵ n + 2d + 5q = 248 ⇒ (2)

∵ n + 2 d + 10q = 443 ⇒ (3)

∴ 5q = 195

- Divide both sides by 5

∴ q = 39

Substitute the value of q in equations (1) and (2)

∵ n + d + q = 78 ⇒ (1)

∴ n + d + 39 = 78

- Subtract 39 from both sides

∴ n + d = 39 ⇒ (4)

∵ n + 2d + 5q = 248 ⇒ (2)

∴ n + 2d + 5(39) = 248

∴ n + 2d + 195 = 248

- Subtract 195 from both sides

∴ n + 2d = 53 ⇒ (5)

Subtract equation (4) from equation (5)

∵ n + d = 39 ⇒ (4)

∵ n + 2d = 53 ⇒ (5)

∴ d = 14

Substitute the value of d in equation (4)

∵ n + d = 39 ⇒ (4)

∴ n + 14 = 39

- Subtract 14 from both sides

∴ n = 25

Jamie has 25 nickels, 14 dimes and 39 quarters in his collection

Learn more:

You can learn more about solving system of equations in

brainly.com/question/13168205

brainly.com/question/2115716

#LearnwithBrainly

5 0
3 years ago
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