Question

Identify each expression and value that represents the area under the curve y= x^2+4 on the interval [-3, 2].

Answer 1

The area is given exactly by the definite integral,

$\displaystyle\int_{-3}^2(x^2+4)\,\mathrm dx=\left(\frac{x^3}3+5x\right)\bigg|_{-3}^2=\frac{95}3\approx31.67$

We can write this as a Riemann sum, i.e. the infinite sum of rectangular areas:

• Split up the integration interval into n equally-spaced subintervals, each with length (2 - (-3))/n = 5/n - - this will be the width of each rectangle. The intervals would then be

[-3, -3 + 5/n], [-3 + 5/n, -3 + 10/n], …, [-3 + 5(n - 1)/n, 2]

• Over each subinterval, take the function value at some point x * to be the height.

Then the area is given by

$\displaystyle\lim_{n\to\infty}\sum_{k=1}^nf(x^*)\Delta x_k=\lim_{n\to\infty}\sum_{k=1}^nf(x^*)\frac5n$

Now, if we take x * to be the left endpoint of each subinterval, we have

x * = -3 + 5(k - 1)/n   →   f (x *) = (-3 + 5(k - 1)/n)² + 4

If we instead take x * to be the right endpoint, then

x * = -3 + 5k/n   →   f (x *) = (-3 + 5k/n)² + 4

So as a Riemann sum, the area is represented by

$\displaystyle\lim_{n\to\infty}\sum_{k=1}^n\left(\left(-3+\frac{5k}n\right)^2+4\right)\frac5n$

and if you expand the summand, this is the same as

$\displaystyle\lim_{n\to\infty}\sum_{k=1}^n\left(13-\frac{30k}n+\frac{25k^2}{n^2}\right)\frac5n=\lim_{n\to\infty}\sum_{k=1}^n\left(\frac{65}n-\frac{150k}{n^2}+\frac{125k^2}{n^3}\right)$

So from the given choices, the correct ones are

• row 1, column 1

• row 2, column 2

• row 4, column 2

Answer 2

Answer:

Step-by-step explanation: