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dedylja [7]
3 years ago
10

The measures of two supplementary angles are 8w + 58 and 16w + 14. Find the measures of the angles

Mathematics
1 answer:
Vikki [24]3 years ago
6 0

Answer:

34

Step-by-step explanation

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Answer to cheek your knowledge
scZoUnD [109]

Answer:

D - ASA

This should be the answer since FH and IG can be said to be parallel and therefore we can find both alternate angles or a vertical opposite angle with one side given. We know that ΔFHJ is reduced by a factor of 2 to get ΔGIJ.

7 0
2 years ago
Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.
fredd [130]

\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}

\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}

so the ODE is indeed exact and there is a solution of the form F(x,y)=C. We have

\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)

\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)

f'(y)=0\implies f(y)=C

\implies F(x,y)=x^2y^3+\ln(x+y^2)=C

With y(1)=2, we have

8+\ln9=C

so

\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}

8 0
2 years ago
What is 5.06 times 2.10. Pease show work
Alecsey [184]

your \: answer \: is \: 10.626

im \: sorry \: i \: cant \: show \: work \: i \: used \: a \:   calculator

3 0
3 years ago
Find the volume of this sphere.
Sholpan [36]
<h3>Calculate the volume of the sphere</h3>

To start finding the volume of this sphere, we get the following data:

  • π = 3
  • r = 2 ft²

To find the volume we apply the following formula:

  • \boldsymbol{\sf{V= \dfrac{3}{4}\pi r^{2}  }}, where
  • v = volume
  • π  = pi
  • r = radius

We substitute our data in the formula and solve:

Substituting values into the equation

  • \boldsymbol{\sf{V=\dfrac{3}{4}*3*(2 \ ft)^{3}  }}

Calculate exponent cubed

  • \boldsymbol{\sf{V=\dfrac{3}{4}*3*8 \ ft^{3}  }}

Multiplying

  • \boxed{\boldsymbol{\sf{V=32 \ ft^{3} }}}

Therefore, the volume of the sphere is 32 ft³.

8 0
2 years ago
Read 2 more answers
In a survey sample of 83 respondents, the mean number of hours worked per week is 39.04, with a standard deviation of 11.51. Cal
soldier1979 [14.2K]

Given that,

Sample size= 83

Mean number= 39.04

Standard deviation= 11.51

We know the critical t-value for  95% confidence interval which is equal to 1.989.

We also know the formula for confidence interval,

CI=( mean number - critical t-value*standard deviation/(sample size)^(1/2), mean number + critical t-value*standard deviation/(sample size)^(1/2))

So, we have

CI= (39.04 - 1.989*11.51/83^(1/2), 39.04 + 1.989*11.51/83^(1/2)

CI= (39.04 - 2.513,39.04 + 2.513)

CI= (36.527,41.553)

Therefore, 95% confidence interval for these data is (36.527,41.553), and this result interpret that the true value for this survey sample lie in the interval (36.527,41.553).

8 0
3 years ago
Read 2 more answers
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