3(x-4)>= 5x+2
Distributing 3 on x-4
3(x)-3(4)>=5x+2
3x-12>=5x+2
Now we need to move x terms together and the numbers together and for that we subtract 5x to both sides and add 12 to both sides
-2x >=14
Now we need to get rid of -2, and for that we divide both sides by -2 and on dividing by negative number, the sign of inequality change , that is
x<=-7
-12y = -17x - 36
divide through by -12:-#y = -17/-12 x + 3
slope = 17/12
Answer:
h(8q²-2q) = 56q² -10q
k(2q²+3q) = 16q² +31q
Step-by-step explanation:
1. Replace x in the function definition with the function's argument, then simplify.
h(x) = 7x +4q
h(8q² -2q) = 7(8q² -2q) +4q = 56q² -14q +4q = 56q² -10q
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2. Same as the first problem.
k(x) = 8x +7q
k(2q² +3q) = 8(2q² +3q) +7q = 16q² +24q +7q = 16q² +31q
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Comment on the problem
In each case, the function definition says the function is not a function of q; it is only a function of x. It is h(x), not h(x, q). Thus the "q" in the function definition should be considered to be a literal not to be affected by any value x may have. It could be considered another way to write z, for example. In that case, the function would evaluate to ...
h(8q² -2q) = 56q² -14q +4z
and replacing q with some value (say, 2) would give 196+4z, a value that still has z as a separate entity.
In short, I believe the offered answers are misleading with respect to how you would treat function definitions in the real world.
4xAnswer: y=9-4x
Step-by-step explanation: Subtract 4X from both sides
