Just plug in values till u get 7
3(2) + (1/5)5 = 7
6 + 5/5 = 7
6 + 1 = 7
7 = 7
Answer:
<em>(D)</em>
Step-by-step explanation:
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Answer:
Below in bold.
Step-by-step explanation:
If the 3 points are on the circle with the given center then the distance from each point to the center will all be equal. This distance will be the radius of the circle.
Distance of P (2, 5) from the center (4, 2)
= √( (5-2)^2 + (2-4)^2)
= √(9 + 4)
= √13.
For Q (6, -1)this distance is:
= √(6-4)^2 + (-1-2)^2)
= √13.
For R (7, 4) his distance is:
= √(7-4)^2 + (4-2)^2)
= √13
These distances are the same so the points P, Q and R lie on the circle.
The midpoint of PQ
= (2+6)/2 , (5 - 1)/2
= (4, 2).
Which is the center so this verifies the second part.
A function is shifted vertically upwards/downwards by adding/subtracting a constant value to the function.
In this case f(x) was shifted upwards by 3 units.
Sin³(x)cos⁴(x) = sin(x)[cos⁴(x) - cos⁶(x)]
sin(x) sin(x)
sin²(x)cos⁴(x) = cos⁴(x) - cos⁶(x)
sin²(x)cos⁴(x) = cos⁴(x)[1] - cos⁴(x)[cos²(x)]
sin²(x)cos⁴(x) = cos⁴(x)[1 - cos²(x)}
cos⁴(x) cos⁴(x)
sin²(x) = 1 - cos²(x)
+ cos²(x) + cos²(x)
1 = 1
