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3 years ago

I need help setting the equation up??

Mathematics

1 answer:

Alexus [3.1K]3 years ago

5 0

Use height over shadow and solve for x

5.5 X
---- = ----
8 33

Find a common denominator and you're all set

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HELP IAM BEING TIMED

MaRussiya [10]

Answer:

Step-by-step explanation:

given y = kx

To find k use the x and y values of the coordinate point given (- 5, 3)

k = $\frac{y}{x}$ = $\frac{3}{-5}$ = - $\frac{3}{5}$

7 0

3 years ago

Read 2 more answers

Solve this recurrence relation an= -an-2 a1=1 a2=2

Lesechka [4]

Answer:

Give Full Question ...I think this question is incomplete

3 0

3 years ago

The lines 2x=ky+2 and (k+1)x=6y-3 have same gradient. Find possible values of k

faust18 [17]

Answer:

k = 3 or k = -4

(Anyone can correct me if I'm wrong)

Step-by-step explanation:

$2x=ky+2\to\ eq1\\(k+1)x=6y-3\to\ eq2\\$Change to this form: $y=mx+c\\ky=2x-2\\y=\frac{2x-2}{k}\\$gradient of eq1: $\frac{2}{k}\\6y=(k+1)x+3\\y=\frac{(k+1)x+3}{6}\\y=\frac{k+1}{6} x+\frac{3}{6}\\y= \frac{k+1}{6} x+\frac{1}{2}\\$gradient of eq1: $\frac{k+1}{6}\\$Since gradient, m, is the same for both lines,$\\\frac{2}{k}=\frac{k+1}{6}\\12=k^{2}+k\\k^{2}+k-12=0\\(k-3)(k+4)=0\\k=3 $ or $ k=-4$

6 0

3 years ago

Jay factored the 4 term polynomial : x^3 - 9x +2x^2 - 18 and decided that the complete factorization was : ( x + 2 ) (x^2-9 ). B

labwork [276]

Answer:

$x^3-9x+2x^2-18\left(x+2\right)\left(x+3\right)\left(x-3\right)$

Step-by-step explanation:

we are given that $x^3-9x+2x^2-18$

w are sked to step by step factorise the above polynomial

$\left(x^3+2x^2\right)+\left(-9x-18\right)$

$-9\mathrm{\:from\:}-9x-18\mathrm{:\quad }-9\left(x+2\right)$

$-9x-9\cdot \:2$

$-9\left(x+2\right)$

$\mathrm{Factor\:out\:}x^2\mathrm{\:from\:}x^3+2x^2\mathrm{:\quad }x^2\left(x+2\right)$

$-9\left(x+2\right)+x^2\left(x+2\right)$

$\left(x+2\right)\left(x^2-9\right)$

$x^2-9:\quad \left(x+3\right)\left(x-3\right)$

$x^2-9$

$\mathrm{Rewrite\:}9\mathrm{\:as\:}3^2$

$=x^2-3^2$

$\mathrm{Apply\:Difference\:of\:Two\:Squares\:Formula:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)$

$x^2-3^2=\left(x+3\right)\left(x-3\right)$

Hence

$x^3-9x+2x^2-18=\left(x+2\right)\left(x+3\right)\left(x-3\right)$

a) The jay mistake was he did not factorise $x^3-9x+2x^2-18x^2-9 furtherb) the complete answer wil be [tex]x^3-9x+2x^2-18\left(x+2\right)\left(x+3\right)\left(x-3\right)$

8 0

3 years ago

Read 2 more answers

How would you find the area or perimeter of this shape?

Fittoniya [83]

The perimeter of a given shape implies the sum of all its sides. While the area of a given shape is the total value of space it would cover on a 2-dimensional plane.

The perimeter of the shape is 104 cm.

The area of the shape is 640 $cm^{2}$ .

The perimeter of a given shape implies the sum of all its length of sides., such that the value of each individual side is summed to a total value.

The area of a given shape is the total value of space it would cover on a 2-dimensional plane. The area of shapes depends on the type of shape.

In the given question, the given shape has 12 sides. Some of these sides can sum up to a given length as shown in the diagram.

So that;

perimeter = 2 + 32 + 10 + 10 + 2 + 32 + 8 + 8

= 104 cm

Thus, the perimeter of the shape is 104 cm

ii. The area of the shape = length x width

= 32 x 20

= 640 $cm^{2}$

Therefore, the area of the given shape is 640 $cm^{2}$ .

for more clarifications on the perimeter and area of a plane shape, visit: brainly.com/question/22909518

#SPJ 1

4 0

2 years ago