The true statement about the triangle is (a) b^2 + c^2 > a^2
<h3>How to determine the true inequality?</h3>
The sides are given as:
a, b and c
The angle opposite of side length a is an acute angle
The above means that:
The side a is the longest side of the triangle.
The Pythagoras theorem states that:
a^2 = b^2 + c^2
Since the triangle is not a right triangle, and the angle opposite a is acute.
Then it means that the square of a is less than the sum of squares of other sides.
This gives
a^2 < b^2 + c^2
Rewrite as:
b^2 + c^2 > a^2
Hence, the true statement about the triangle is (a) b^2 + c^2 > a^2
Read more about triangles at:
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Answer:
18x+36
Step-by-step explanation:
9(2x+6) - 18
Distribute
9*2x + 9 *6 -18
18x +54 -18
Combine like terms
18x+36
Answer:
B
Step-by-step explanation:
B'(7, -4)
Let the pre-image coordinates be (x,y)
Consider x-coordinate,
x + 4 = 7
x = 3
Consider y-coordinates,
y + 5 = -4
y = -9
pre-image coordinates is (3, -9)
I need a picture of the figure so I can calculate it.
