ANSWER:
In triangles BEC and AED
1)BC=AD(given)
2)Angle BCD= Angle ADC(given)
Then,Angles BCE=Angle ADE
3)Angle BEC=Angle AED(vertically opposite angles)
Thus,triangleBEC=~triangle AED( by AAS rule)
Thus,DE=CE (By CPCTC)
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Answer:
2000
Step-by-step explanation:
S.I=P×rate / 100×time
30000×8 / 100×5/6
=2000
The answer is 28 years
At = A0 * e^(-k * t)
At = 12 g
A0 = 15 g
k = 7.9 × 10^-3 = 0.0079
t = ?
12 = 15 * e^(-0.0079 * t)
12/15 = e^(-0.0079 * t)
0.8 = e^(-0.0079 * t)
Logarithm both sides (because ln(e) = 1:
ln(0.8) = ln(e^(-0.0079 * t))
ln(0.8) = (-0.0079 * t) * ln(e)
-0.223 = -0.0079 * t
t = -0.223 / -0.0079
t = 28.23
t ≈ 28 years
Answer:
Angle 3 = 86.8
Angle 6 = 96.4
Angle 7 = 93.2
Step-by-step explanation:
Given :
angle 6 = 4x + 10
angle 7 = 2x + 40
=> angle 6 + angle 7 = 180° { linear pair }
=> 4x+10 +2x+40 = 180
=> 6x+50 = 180
=> 6x = 180-50
=> 6x = 130
=> x = 130/6
=> x = 21.6
so ,the measure of angle 6 = 4x + 10 = 4(21.6) +10 = 86.4+10 = 96.4
the measure of angle 7 = 2x + 40 = 2(21.6) +40 = 43.2+50 = 93.2
now angle 7 = angle 4 + angle 5
and angle 3 + angle 4 + angle 5 = 180°
so, angle 7 + angle 3 = 180
=> 93.2 + angle 3 = 180
=> angle 3 = 180 - 93.2
=> angle 3 = 86.8
