Help me with this problem please

Mathematics

1 answer:

andreev551 [17]3 years ago

3 0

Answer:

$y = \frac{ - 3x + 6}{2} = \\ x = 4 \\ y = \frac{ - 3 \times 4 + 6}{2} = \frac{ - 12 + 6}{2} = \frac{ - 6}{2} = - 3$

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Answer:

$\purple { \bold{ \frac{ (x - 3)}{3x - 18} }}$

Step-by-step explanation:

$\frac{x + 3}{ {x}^{2} + 7x + 12 } . \frac{ {x}^{2} + x - 12}{3x - 18} \\ \\ = \frac{x + 3}{ {x}^{2} + 4x + 3x + 12 } . \frac{ {x}^{2} + 4x - 3x - 12}{3(x - 6)} \\ \\ = \frac{x + 3}{ {x}(x + 4) + 3(x + 4) } . \frac{ {x}(x + 4) - 3(x + 4)}{3(x - 6)} \\ \\ = \frac{ \cancel{(x + 3)}}{ (x + 4) \cancel{(x + 3)} } . \frac{ (x + 4) (x - 3)}{3(x - 6)} \\ \\ = \frac{1}{ \cancel{ (x + 4)} } . \frac{ \cancel{ (x + 4)} (x - 3)}{3(x - 6)} \\ \\ \red{ \bold{= \frac{ (x - 3)}{3x - 18} }}\\ \\$