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IgorC [24]
3 years ago
5

Help me with this problem please

Mathematics
1 answer:
andreev551 [17]3 years ago
3 0

Answer:

y =   \frac{ - 3x + 6}{2}  =  \\ x = 4 \\ y =  \frac{ - 3 \times 4 + 6}{2}  =  \frac{ - 12 + 6}{2}  =   \frac{ - 6}{2}  =  - 3

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PLEASE HELP THIS IS DUE IN 20 MINUTES
Ilia_Sergeevich [38]

Answer:

I think shape A is just reflected, and make Shape B.

The reflection line is on 2 of the y axis

Step-by-step explanation:

5 0
3 years ago
What is the mean, variance, and standard deviation of the values? Round to the nearest tenth. 1,9,4,12,13,13
tankabanditka [31]

To compute the mean, you simply have to sum all the elments in the data set and the divide the sum by the number of elements:


M = \frac{1+4+9+12+13+13}{6} = \frac{52}{6} = 8.6


To compute the variance, we first need to compute the distance of each element from the mean. To do so, we build a "parallel" dataset, given by the difference of every value and the mean:


D' = 1-8.6,9-8.6,4-8.6,12-8.6,13-8.6,13-8.6


D' = -7.6, 0.4, -4.6, 3.4, 4.4, 4.4


Now we need those difference squared:


(D')^2 = 57.76, 0.16, 21.16, 11.56, 19.36, 19.36


The variance is the mean of this new vector, so


\sigma^2 = \frac{57.76+ 0.16+ 21.16+ 11.56+ 19.36+ 19.36}{6} = \frac{129.36}{6} = 21.6


Finally, the standard deviation is simply the square root of the variance, so you have


\sigma = \sqrt{21.6} = 4.6

8 0
3 years ago
PLEASE HELP!!! It would be amazing if you could show the steps!!
r-ruslan [8.4K]

Answer:

A:

|7-x|

B:

With absolute value equations, you can make two equations.

|7-x|-4\\xx>11

5 0
4 years ago
The rectangular rug in Marcia's living room measures 12 feet by 109 inches. What is the rug's area in square feet?
Marrrta [24]

Answer:

109 square feet.

Step-by-step explanation:

109 in: = 109/12 = 9.0833333.... = 9 5/60 = (540+5)/60 = 545/60

Area = L*w

L = 545/60 feet

W = 12 feet

Area = 545/60 *  12

Area = 545*12/60

Area = 545 /5 = 109 square feet.  

3 0
3 years ago
A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student
yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

The information provided is as follows:

n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43

The critical value of <em>z</em> for 98% confidence level is,

z_{\alpha/2}=z_{0.02/2}=2.326

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

     =(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0
3 years ago
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