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I am Lyosha [343]
4 years ago
12

Simplify 6/2√3-√6+√6/√3+√2- 4√3/√6-√2

Mathematics
1 answer:
kkurt [141]4 years ago
7 0

Answer:

-sqrt(2) + 3 sqrt(3) - sqrt(6)

Step-by-step explanation:

Simplify the following:

(6 sqrt(3))/2 - sqrt(6) + (sqrt(6))/(sqrt(3)) + sqrt(2) - (4 sqrt(3))/(sqrt(6)) - sqrt(2)

6/2 = (2×3)/2 = 3:

3 sqrt(3) - sqrt(6) + (sqrt(6))/(sqrt(3)) + sqrt(2) - (4 sqrt(3))/(sqrt(6)) - sqrt(2)

Rationalize the denominator. (sqrt(6))/(sqrt(3)) = (sqrt(6))/(sqrt(3))×(sqrt(3))/(sqrt(3)) = (sqrt(6) sqrt(3))/3:

3 sqrt(3) - sqrt(6) + (sqrt(6) sqrt(3))/3 + sqrt(2) - (4 sqrt(3))/(sqrt(6)) - sqrt(2)

sqrt(6) sqrt(3) = sqrt(6×3):

3 sqrt(3) - sqrt(6) + (sqrt(6×3))/3 + sqrt(2) - (4 sqrt(3))/(sqrt(6)) - sqrt(2)

6×3 = 18:

3 sqrt(3) - sqrt(6) + (sqrt(18))/3 + sqrt(2) - (4 sqrt(3))/(sqrt(6)) - sqrt(2)

sqrt(18) = sqrt(2×3^2) = 3 sqrt(2):

3 sqrt(3) - sqrt(6) + (3 sqrt(2))/3 + sqrt(2) - (4 sqrt(3))/(sqrt(6)) - sqrt(2)

(3 sqrt(2))/3 = 3/3×sqrt(2) = sqrt(2):

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) - (4 sqrt(3))/(sqrt(6)) - sqrt(2)

Rationalize the denominator. (-4 sqrt(3))/(sqrt(6)) = (-4 sqrt(3))/(sqrt(6))×(sqrt(6))/(sqrt(6)) = (-4 sqrt(3) sqrt(6))/6:

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) + (-4 sqrt(3) sqrt(6))/6 - sqrt(2)

The gcd of -4 and 6 is 2, so (-4 sqrt(3) sqrt(6))/6 = ((2 (-2)) sqrt(3) sqrt(6))/(2×3) = 2/2×(-2 sqrt(3) sqrt(6))/3 = (-2 sqrt(3) sqrt(6))/3:

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) + (-2 sqrt(3) sqrt(6))/3 - sqrt(2)

sqrt(3) sqrt(6) = sqrt(3×6):

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) - 2/3 sqrt(3×6) - sqrt(2)

3×6 = 18:

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) - (2 sqrt(18))/3 - sqrt(2)

sqrt(18) = sqrt(2×3^2) = 3 sqrt(2):

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) - 2/3 3 sqrt(2) - sqrt(2)

Combine powers. (-2×3 sqrt(2))/3 = 2 sqrt(2)×3^(1 - 1) (-1):

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) - 2 sqrt(2)×3^(1 - 1) - sqrt(2)

1 - 1 = 0:

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) - 2 sqrt(2)×3^0 - sqrt(2)

3^0 = 1:

3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) - 2 sqrt(2)×1 - sqrt(2)

Add like terms. 3 sqrt(3) - sqrt(6) + sqrt(2) + sqrt(2) - 2 sqrt(2) - sqrt(2) = -sqrt(2) + 3 sqrt(3) - sqrt(6):

Answer: -sqrt(2) + 3 sqrt(3) - sqrt(6)

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Snowcat [4.5K]

Answer:

20

Step-by-step explanation:

First step is finding an angle in the rightmost triangle (angle K)

Using TOA we have

Tan(x)=4/8

x=26.565

which means that 90-26.565= 63.4349 will give us angle K in regards to the left triangle

Using this we can solve for JM

Tan(63.4349)=x/8

8tan(63.4349=x

x=16

So if JM = 16

and LM=4

take their sum to find JL

16+4=20

4 0
3 years ago
Evaluate the following expression when x = 3 and y = 4:
JulijaS [17]
I don't understand.  What are the values given?  Are they values of an x,y plot?
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5 0
4 years ago
Which function passes through the points (2, 3) and (4, 4)?
Rina8888 [55]

Answer:

C. y=1/2x+2

Step-by-step explanation:

1. Find the slope using the slope formula.

Slope formula: y2-y1/x2-x1

Let the y-value in the second ordered pair (4,4) be y2, and the 3 in the first ordered pair (2,3) be y1. 4 and 2 from these ordered pairs will be x2 and x1.

Plug these values into the equation and simplify.

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=1/2

Slope is 1/2

2. Choose one of the ordered pairs and plug those numbers and the slope into the point-slope formula.

Point slope formula: y-y1=m(x-x1). M represents the slope, and the x1 and y1 represent the values of the ordered pair.

Let's use the pair (4,4).

y-4=1/2(x-4)

3. Simplify the equation to convert to y=mx+b format.

Multiply the inside of the parentheses by 1/2.

y-4=1/2x-2

Add 4 to both sides.

y=1/2x+2

3. C is your answer, for it matches what you found in the calculations.

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natulia [17]
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4 years ago
If=y=1 z=2<br>(2y + z) (2y-z)​
snow_tiger [21]

Answer:

answer is 0

Step-by-step explanation:

(2×1+2)(2×1-2)

(4×0)

0

5 0
3 years ago
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