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4 years ago

15

The jars of paint in the art room have different amounts of paint. The green paint jar is 4/8 full. The purple paint jar is 4/6f

ull which paint jar is less full

1 answer:

natulia [17]4 years ago

7 0

4/8 is less full because it's only half compared to 4/6 which is 1.5

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-1/2 w -3/5= 1/5w<br><br> W=

Vinil7 [7]

The exact form is: w = -6/7

8 0

3 years ago

Which equation can be used to solve for b?<br> B<br> 5 cm<br> 10 cm<br> 30°

kati45 [8]

The Question is Incomplete The complete question with figure is below.

Answer:

Therefore the equation to solve for b is

$\tan 30 = \dfrac{5}{b}$

Step-by-step explanation:

Given:

In Right Angle Triangle ABC

∠C = 90°

BC = 5 cm

AB = 10 cm

∠A = 30°

To Find:

b = ?

Solution:

In Right Angle Triangle ABC Tangent identity we have

$\tan A = \dfrac{\textrm{side opposite to angle A}}{\textrm{side adjacent to angle A}}$

Substituting the values we get

$\tan 30 = \dfrac{BC}{AC}\\\\\tan 30 = \dfrac{5}{b}$

Therefore the equation to solve for b is

$\tan 30 = \dfrac{5}{b}$

6 0

3 years ago

What is this?<br><br> :) Help Plz!!!

Eduardwww [97]

Im 70% sure its blue x=1,x=-5/2

Hope i helped if did plz mark as brainliest^-^

3 0

3 years ago

Which expressions describe the end behaviors of the function f(x)=2^x+3. modeled by the graph attached to this. Choose all that

Gala2k [10]

As x increases without bound, f(x) also increases without bound

3 0

3 years ago

a. Determine all bijections from the {1,2,3} into {a,b,c}. b. Determine all bijections from {1, 2, 3} into {a,b,c,d}.

avanturin [10]

Part A

There are 6 bijections from {1,2,3} to {a,b,c}. This is effectively the same as asking the question "how many ways are there to arrange {a,b,c} where order matters?" We use a factorial to answer this question.

3 factorial = 3! = 3*2*1 = 6

You can also use a permutation, which is composed of factorials, to get the same answer.

======================================================

Part B

There are no bijections from {1,2,3} to {a,b,c,d}. Why is this? Because a bijection has two properties: it must be one-to-one, and it must be onto. The term "onto" in mathematics means "every value in the range is targeted". In the case of the range {a,b,c,d} it is not possible for each value to show up. This is because there are only three items in the domain {1,2,3}. You'll always be one letter short.

As you can probably guess, a bijection is only possible if and only if n(D) = n(R), where D and R are the domain and range respectively. The notation n(D) represents the count or number of items in set D.

3 0

3 years ago