the final speed in m/s of the 10.0 kg is 2.53 m/s .
<u>Step-by-step explanation:</u>
Here we have , A 10.0 kg and a 2.0 kg cart approach each other on a horizontal friction less air track. Their total kinetic energy before collision is 96 ). Assume their collision is elastic. We need to find What is the final speed in m/s of the 10.0 kg mass if that of the 2.0 kg mass is 8.0 m/s . Let's find out:
We know that in an elastic collision :
⇒ Total kinetic energy before collision = Total kinetic energy after collision
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Therefore , the final speed in m/s of the 10.0 kg is 2.53 m/s .
No because 5+3(1-x) it is 5+3-3x them 8-3x not 8-8x
Answer:
8. X = 10.5 and 19. X = 5
Step-by-step explanation:
8. You know that a triangle interior angles should add up to 180° so:
(10x - 11) + (3x - 2) + (3x + 1) = 180
180 = 16x - 12
168 = 16x
The you divide each side by 16:
168 ÷ 16 = 16x ÷ 16
X = 10.5
10. You know that a straight line equals 180° and interior angles add up to 180° so:
1st you do 180 - 151 = 29°
2nd (11x - 1) + (20x - 3) + (29) = 180
180 = 31x + 25
155 = 31x
The you divide each side by 31:
155 ÷ 31 = 31x ÷ 31
X = 5
15−2x−8−3x=−x−12+4x+43
now combine all the like terms on each side.
Add -2x and -3x
subtract 15 and -8....you subtract because the sign are different
now do the same for the other side
−5x+7=−x−12+4x+43
−5x+7=3x+31
bring the x value from the right side to the left side.
−5x+7−3x=31
combine like terms on left side
−8x+7=31
now move +7 to the right side which become..
−8x=−7+31
−8x=24
we will need to single out X by dividing
answer: X= -3
Answer:
54
Step-by-step explanation:
RSM homework lol
made equation, then solved it.
hope this helps!
