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julsineya [31]
3 years ago
14

How do you solve 1 1/6 × 2 1/3

Mathematics
1 answer:
Bas_tet [7]3 years ago
3 0

Answer:

2 1/3

Step-by-step explanation:

1. first we have to turn the mixed numbers into improper fractions.

after rewriting them, your new problem would be 7/6 x 7/3.

2. now you just multiply the fractions together and your final answer would be 49/18, or 2 1/3.

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Can someone help me on this math
Tomtit [17]
58.96 or 1887/32 id the answer
5 0
3 years ago
A group of students was discussing the meaning of this statement. They were arguing back and forward about whether the converse
Savatey [412]

Answer:

The statement is missing. The statement is -- "A ray can be part of a line."

The answer is : The converse is not true, so Jahmiah is correct.

Step-by-step explanation:

A conditional statement is represented by showing p → q. It means if p is correct or true,  then q is also correct or true.

And the converse of p → q can be shown as  q → p.

But we know that the converse of a statement is not always true, it may be true and may not be true.

In the context, the statement is " a ray can be a part of a line." And so the converse would be  "A line can be a part of the ray".

So by definition we know that a line is continuous line having no end points, it extends in one direction. While a ray starts from a point and extends to infinity in one direction.

Thus ray is part of line but line is not a part of the ray. So the converse of the statement is not correct.

Hence, Jahmiah is correct.

6 0
3 years ago
Match the logarithmic functions with their corresponding x-values
cricket20 [7]
We have the following functions:
 log2x=5
 log10x=3
 log4x=2
 log3x=1
 log5x=4
 Let's rewrite each function to solve for x:
 x=2^5=32
 x=10^3=1000
 x=4^2=16
 x=3^1=3
 x=5^4=625
 Answer:
 Matching each function with the solution we have:
 log2x=5 ----------->32
 log10x=3---------->1000
 log4x=2------------>16 
 log5x=4------------>625
3 0
3 years ago
Write down the exact value of cos 60 degrees
Misha Larkins [42]

Answer:

.5

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
B. Determine the values of a and b so that f is continuous.<br><br> Please help!
wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to  4a-2b+3 = 4\\\\  \therefore \ \ 4a-2b = 1\\\\

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\  

So,

\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3

\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\

In equation a multiply the by -2 and then add in the equation b:

\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to   a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to   -2b = -1\\\\ \to b = \frac{1}{2}  

So, the value of a \ and \ b= \frac{1}{2}

4 0
3 years ago
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