Question

A 10.0 kg and a 2.0 kg cart approach each other on a horizontal frictionless air track. Their

Answer 1

the  final speed in m/s of the 10.0 kg is 2.53 m/s .

Step-by-step explanation:

Here we have , A 10.0 kg and a 2.0 kg cart approach each other on a horizontal friction less air track. Their  total kinetic energy before collision is 96 ). Assume their collision is elastic. We need to find What is the  final speed in m/s of the 10.0 kg mass if that of the 2.0 kg mass is 8.0 m/s . Let's find out:

We know that in an elastic collision :

⇒ Total kinetic energy before collision  = Total kinetic energy after collision

⇒ $96 = \frac{1}{2}M_1(v_1)^2 + \frac{1}{2}M_2(v_2)^2$

⇒ $96 = \frac{1}{2}(10)(v_1)^2 + \frac{1}{2}(2)(8)^2$

⇒ $96=5(v_1)^2 + 64$

⇒ $5(v_1)^2 =32$

⇒ $(v_1)^2 =6.4$

⇒ $v_1 =2.53 m/s$

Therefore , the  final speed in m/s of the 10.0 kg is 2.53 m/s .