turn them both into fractions
10 1/2 = 21/2
2 1/4 = 9/4
so you have 21/2 / 9/4
invert 2nd one and multiply
21/2 * 4/9 = 21*4 over 2*9 or 84/18 = 4 2/3
The answer is 5.6 I hope this helps
The answer is in the inserted picture.
Answer:
P(X ≥ 5) = 0.6667
Step-by-step explanation:
Waiting for a train that comes once in 0 to 15 minutes is a uniform probability distribution problem.
For a uniform probability distribution, the probability function is given as
P(X) = f(x) = [1/(b-a)] for (a≤x≤b)
where a = lower limit of the uniform distribution sample space = 0 mins
b = upper limit of the uniform distribution sample space = 15 mins
But P(X≥x) = 1/(b-a) ∫ dx (with the Integral evaluated from x to b)
So, the probability that a person would wait at least 5 minutes for a train = P(X ≥ 5)
P(X ≥ 5) = 1/(b-a) ∫¹⁵₅ dx = 1/(15-0) ∫¹⁵₅ dx
P(X ≥ 5) = (1/15) × [x]¹⁵₅ = (1/15) × (15 - 5) = (10/15) = (2/3) = 0.6667
Hope this Helps!!!
The EXACT ratio is 7.7:1, but you can round it up to about 8:1