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Thepotemich [5.8K]
3 years ago
15

X^2=1/4 please help me

Mathematics
2 answers:
skelet666 [1.2K]3 years ago
5 0
X² = 1/4 ⇒√⇒ x₁ = 1/2, x₂ = -1/2
Zina [86]3 years ago
3 0

x= 1/2

If you take 1/2 times 1/2 you get 1/4, and 1/2 times 1/2 is the same as 1/2 squared.

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tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A                          Sample B

x_A = 30                              x_B = 50

n_A = 100                             n_B =250

Solving (a): Standard error using formula

First, calculate the proportion of A

p_A = \frac{x_A}{n_A}

p_A = \frac{30}{100}

p_A = 0.30

The proportion of B

p_B = \frac{x_B}{n_B}

p_B = \frac{50}{250}

p_B = 0.20

The standard error is:

SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}

SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}

SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}

SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}

SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}

SE_{p_A-p_B} = \sqrt{0.00274}

SE_{p_A-p_B} = 0.052

Solving (a): Standard error using bootstrapping.

Following the below steps.

  • Open Statkey
  • Under Randomization Hypothesis Tests, select Test for Difference in Proportions
  • Click on Edit data, enter the appropriate data
  • Click on ok to generate samples
  • Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A                          Sample B

x_A = 23                              x_B = 57

n_A = 100                             n_B =250

p_A = 0.230                          p_A = 0.228

So, we have:

SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}

SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}

SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}

SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}

SE_{p_A-p_B} = \sqrt{0.002475064}

SE_{p_A-p_B} = 0.050

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3 years ago
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Brrunno [24]

Answer:

parallel

Step-by-step explanation:

all the details are in the attached picture.

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3 years ago
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guapka [62]
Based on the options given in the picture

The one that would be the result if we construct the line that perpendicular to KL at point M would be :

picture C

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3 years ago
Read 2 more answers
Verify that (cos²a) (2 + tan² a) = 2 - sin² a....<br>​
Sveta_85 [38]

Trigonometric Formula's:

\boxed{\sf \ \sf \sin^2 \theta + \cos^2 \theta = 1}

\boxed{ \sf tan\theta = \frac{sin\theta}{cos\theta} }

Given to verify the following:

\bf (cos^2a) (2 + tan^2 a) = 2 - sin^2 a

\texttt{\underline{rewrite the equation}:}

\rightarrow \sf (cos^2a) (2 + \dfrac{sin^2 a}{cos^2 a} )

\texttt{\underline{apply distributive method}:}

\rightarrow \sf 2 (cos^2a) + (\dfrac{sin^2 a}{cos^2 a} ) (cos^2a)

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\rightarrow \sf 2(1 - sin^2a )  + sin^2 a

\texttt{\underline{distribute inside the parenthesis}:}

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\texttt{\underline{simplify the following}} :

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Hence, verified the trigonometric identity.

7 0
2 years ago
Read 2 more answers
Use long division to find the quotient of 405 and 27
asambeis [7]

27|405 27*1=27
- 27 27*5=135
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135
-135
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0

Answer is 6 :v
7 0
3 years ago
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