Answer:
4c + 6a < = 120 ...4(20) + 6(6) = 116 <== correct
4c + 4a < = 100....4(20) + 4(6) = 104 <== incorrect
Step-by-step explanation:
Answer:
I just did this lesson; this answers are right.
1: Given 1: ∠1 = ∠2, ∠3 = ∠4, D is midpoint of segment BE, BC = DE
2: BD = DE 2: Definition of midpoint
3: BC = BD 3: Substitution
4: Triangle ABD congruent to Triangle EBC 4: ASA
5: ∠A = ∠E 5: CPCTE
Step-by-step explanation:
<span>Let us start with the schnauzers, the easiest one to imagine. Let us assume that there were x number of schnauzers.
Scottie's are 3 more than schnauzers. So their number is x+3
Wire haired terriers are 5 less than twice the number of schnauzers.
So their number is 2x -5 (2x for twice the number of schnauzers)
Now add all these numbers.
That is x + x+3 + 2x-5 = 4x -2
The total number of dogs, 78, is given in the question
Now we know that 4x -2 =78
4x = 78 +2
= 80
Therefore x = 80/4
= 20.
So there were 20 schnauzers, 23 Scottie’s and 35 wire haired terriers</span>
Answer:
It's a parallelogram, angles B and D, and A and C are congruent, lines AB and DC, and BC and AD are congruent.
Step-by-step explanation:
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