Area of a triangle ABC with the given vertices is 3 square units.
Given that, the vertices of a triangle ABC, A(3,-6), B(5,-6), and C(7,–9).
<h3>What is the area of triangle formula in coordinate geometry?</h3>
In Geometry, a triangle is a three-sided polygon that has three edges and three vertices. The area of the triangle is the space covered by the triangle in a two-dimensional plane.
Area of a triangle = ![\frac{1}{2} ( |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%28%20%7Cx_1%28y_2%20-%20y_3%29%20%2B%20x_2%28y_3%20-%20y_1%29%20%2B%20x_3%28y_1%20-%20y_2%29%7C%29)
Here, (x1, y1) = A(3,-6), (x2, y2) = B(5,-6), and (x3, y3) = C(7,–9)
Now, the area of a triangle = 1/2 (|3(-6+9)+5(-9+6)+7(-6+6)|)
= 1/2 (|3(3)+5(-3)+7(0)|)
= 1/2 (|(9-15)|)
= 1/2 × 6
= 3 square units
Therefore, area of a triangle ABC with the given vertices is 3 square units.
To learn more about the area of a area of triangle with vertices visit:
brainly.com/question/26633662.
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