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Goshia [24]
3 years ago
11

I need someone to Solve for r: V=πr2h as quick as you can

Mathematics
1 answer:
DENIUS [597]3 years ago
7 0

Answer:

r = \sqrt{\frac{V}{\pi h }

Step-by-step explanation:

V=πr²h

Isolate r:

r² = \frac{V}{\pi h }

To solve for r, take the square root of both sides:

r = \sqrt{\frac{V}{\pi h }

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Answer:

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If alex is visiting her moms house and eats a pizza that has 6 triangular pieces, how long would it take for alex’s mom to reach
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Answer:

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20 for this question needing help
Radda [10]

Step-by-step explanation:

option C is the answer.

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7 0
2 years ago
Given f(x)=5x^2-2x and 3x^2+x-4. What is (f+g)(x)?
den301095 [7]

Answer:(f + g)(x) = f (x) + g(x)

= [3x + 2] + [4 – 5x]

= 3x + 2 + 4 – 5x

= 3x – 5x + 2 + 4

= –2x + 6

(f – g)(x) = f (x) – g(x)

= [3x + 2] – [4 – 5x]

= 3x + 2 – 4 + 5x

= 3x + 5x + 2 – 4

= 8x – 2

(f  × g)(x) = [f (x)][g(x)]

= (3x + 2)(4 – 5x)

= 12x + 8 – 15x2 – 10x

= –15x2 + 2x + 8

\left(\small{\dfrac{f}{g}}\right)(x) = \small{\dfrac{f(x)}{g(x)}}(  

g

f

​  

)(x)=  

g(x)

f(x)

​  

 

= \small{\dfrac{3x+2}{4-5x}}=  

4−5x

3x+2

​

Step-by-step explanation:

To find the answers, all I have to do is apply the operations (plus, minus, times, and divide) that they tell me to, in the order that they tell me to.

7 0
3 years ago
Read 2 more answers
1. Storing milk at temperatures colder than 35°F can affect its quality of taste. However, storing milk at temperatures warmer t
Zinaida [17]

1.

Storing milk at temperatures smaller than 35°F can affect its quality of taste.

hence  t > 35°F

storing milk at temperatures greater than 40°F is an unsafe food practice. hence

t < 40°F

so correct choice is

C. t > 35 AND t < 40


2.

15| x-7|+4=10|x-7|+4

subtracting 4 both side

15| x-7|+4- 4 =10|x-7|+4 - 4

15| x-7| = 10|x-7|

this is possible when |x-7| = 0

hence x - 7 = 0

x = 7

hence correct choice is

C. only x=7


3.

|x+1|+5=2

we know that , |x+1| ≥ 0

adding 5 both side

|x+1| + 5 ≥ 0 + 5

|x+1| + 5 ≥ 5

hence the relation |x+1|+5=2  is false.

C. no solution


|4x+12|=0

4x+12 = 0

x = -12/4

x = - 3

hence B. solution


|3x|=9

3x = \pm9

x =  \pm9/3

x =  \pm3

hence  

A. two solutions


8 0
3 years ago
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