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tensa zangetsu [6.8K]

3 years ago

8

Please help meeeeeeeeeeeeeeee!!!!!!!!!!!!!!

1 answer:

Ipatiy [6.2K]3 years ago

4 0

Since the model is 1/13 the size of the tent, you multiply 6” by 13 to get 78”. Since you want feet, you divide 78” by 12” because there are 12 inches in a foot and you want to convert the unit to feet. The answer is 6.5 feet or 6.5’

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A 17-inch candle is lit and burns at a constant rate of 1.3 inches per hour. Let t represent the number of hours since the candl

pshichka [43]

Answer

Since the lyla deleted it actually for a good reason let me explain. But you dont just delete random answers, you can give a comment. I can report you for doing that.

So since it burns at 1.3 per hour. Notice that since it gets removed per hour. so it would be 1.3t so it multiplies per hour. Then we need to subtract. Thats because it lowers the length of the candle. So we get the original length - 17 and get the function

f(t) = 17-1.3t

6 0

3 years ago

Find the value of x.

pychu [463]

Knowing that all triangles angles add up to 180*:

24* + x + ? = 180*

Knowing the straight line is 180*:

180* - 122* = 58*

The equation then is:

24* + x + 58* = 180*

Then solve for X:

(82* + x) - 82* = (180*) - 82*

<u>x = 98* or C</u>

7 0

3 years ago

Read 2 more answers

What estimate can you make for 1/2 and 4/6?

densk [106]

1/2 would be rounded to 1 and 4/6 would be rounded to 1

5 0

3 years ago

The area of ABED is 49 square units. Given AGequals9 units and ACequals10 units, what fraction of the area of ACIG is represent

stiks02 [169]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

$A=b^{2}$

where b is the length side of the square

we have

$A=49\ units^2$

substitute

$49=b^{2}$

$b=7\ units$

therefore

$AB=BE=ED=AD=7\ units$

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

$A=(AC)(AG)$

substitute the given values

$A=(9)(10)=90\ units^2$

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

$A=(DE)(DG)$

we have

$DE=7\ units$

$DG=AG-AD=9-7=2\ units$

substitute

$A=(7)(2)=14\ units^2$

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

$A=(EF)(CF)$

we have

$EF=AC-AB=10-7=3\ units$

$CF=BE=7\ units$

substitute

$A=(3)(7)=21\ units^2$

step 5

sum the shaded areas

$14+21=35\ units^2$

step 6

Divide the area of of the shaded region by the area of ACIG

$\frac{35}{90}$

Simplify

Divide by 5 both numerator and denominator

$\frac{7}{18}$

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

5 0

3 years ago

How many times larger is a 10pound dog from a hamster weighing 5/8 pound

lutik1710 [3]

it would be 16 times larger

6 0

3 years ago