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3 years ago

5

How to find slope on a graph?

1 answer:

GalinKa [24]3 years ago

8 0

Well you basically use rise/run so basically you choose two points on the line and you count how many squares it goes up until its on the same line as the other point and then you count how many squares to the side to get to the other point so rise/run ill explain it a lil better

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If two times a number is decreased by 6 the principal square root of this difference is 7less than the number. What is the numbe

Luba_88 [7]

8 jendjdksmsisnmeiehrbdod

6 0

3 years ago

Find the product of (x + 5)(x − 5) and show work

AleksandrR [38]

(x + 5) * (x − 5) =

x² - 25

----------------

x * x = x² and 5 * (-5) = -25

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3 years ago

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Is f(x) =3*(7/4)^x a growth or decay. Please help me it’s urgent!!!!

kupik [55]

Answer:

growth

Step-by-step explanation:

the value under ^x is more than 1

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3 0

3 years ago

Simplify by factoring. Assume that all expressions under radicals represent nonnegative numbers.

Nimfa-mama [501]

<h2>Answer:</h2>

<u>x>0 and working with real numbers</u>

$10x^2\sqrt{2}$

OR

<u>x<0 and working with imaginary/complex numbers</u>

$10\sqrt{2}\sqrt{x^4}$

OR

<u>Leave it like the following for both systems(Real/Complex) numbers</u>

$10\sqrt{2}\sqrt{x^4}$

<h2>Step-by-step explanation:</h2>

$\sqrt{200x^4}$

<u>First simplify</u> $\sqrt{200}$

$\sqrt{200}$

<u>Find a perfect square and a non perfect square, which when you multiply the two squares it gives you</u> $\sqrt{200}$

$\sqrt{100} * \sqrt{2} = \sqrt{200}$

$\sqrt{100} \ \sqrt{2}}$

$10 \sqrt{2}$

<u>Now get the square root of</u> $\sqrt{x^4}$ <u>if we are working with real numbers and x > 0</u>

$\sqrt{x^4} = x^2$

<u>If x not > 0 then just leave as</u> $\sqrt{x^4}$

<u>Now combine it all</u>

$10x^2\sqrt{2}$

OR

$10\sqrt{2}\sqrt{x^4}$

5 0

3 years ago

NEED HELP ASAP PLEASE

Mariulka [41]

undefined slope; y intercept=3

3 0

3 years ago