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Margaret [11]
3 years ago
7

a number cube numbered 1-6 is rolled 30 times and lands on an even number 18 times. How does this frequency compare to the expec

ted frequency based on the probability of the number cube landing on an even number?

Mathematics
1 answer:
Korolek [52]3 years ago
8 0

Answer:

The frequency is 3 more than expected

Step-by-step explanation:

There are 3 favourable outcomes: {2, 4, 6}

There are 6 possible outcomes: {1, 2, 3, 4, 5, 6}

probability of the number cube landing on an even number = favourable outcomes / possible outcomes = 3/6 = 1/2

If the cube is rolled 30 times, it is expected that in 1/2*30 = 15 times landed on an even number. The frequency: 18 is 3 more than expected

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Error in question aside, and  ASSUMING the hexagon is regular, you can apply the principle that
1. the sum of exterior angles of ANY polygon is 360.
2. the sum of exterior angles and interior angles at EACH vertex is 180.
3. Multiply sum from (2) above by the number of vertices and subtract 360 gives the sum of the interior angles.
4. IF the polygon is regular (all angles equal), then each interior angle equals the result from (3) divided by n, the number of vertices.

Example for a regular heptagon (7 sides, 7 verfices).
1. Sum of exterior angles = 360
2. sum of interior and exterior angles at EACH vertex=180
3. multiply 180 by 7, subtract 360
180*7-360=900
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Step-by-step explanation:

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