Answer:
The work done to pump all of the kerosene from the tank to an outlet is
Step-by-step explanation:
The work is defined by:
(1)
The force here will be the product between the volume and the kerosene weighing, so we have :

This force will be in-lbs.
Where R is the radius (3 feet)
Then using (1), we have:
Here 8-y is a distance at some point of the tank. Now, to get the work done from the base to the top of the tank we will need to take integral from 0 to 8 feet.




Therefore, the work done to pump all of the kerosene from the tank to an outlet is
I hope it helps you!
Coordinate of A are (0,0)
Coordinates of A' are (5,2)
We can find the distance from A to A' using the distance formula:
Thus, rounded to nearest hundredth, AA' is equal to 5.39
To find out how much more you walked today, you want to find the difference between the two days, which is 10,000-(<span>3y - 2c + 600) = 9400-3y+2c using the distributive property (the negative sign in front of the parenthesis is essentially a -1)</span>
-3x-5+2x=6
2x-3x-5=6
-1x-5=6
-x-5=6
-x=11
x=11
an equivilent equaiton is x=11
Answer:
0.8 or .8
Step-by-step explanation:
multiply the top and bottom by 10
so 8/10=80/100
to get the decimal form, just divide 8 by 10 and it should give you 0.8