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Colt1911 [192]
3 years ago
14

Frank purchased a new ice box having 2kg capacity. He wants it to be full with ice cubes. He measured the ice cubes to be 3.5 cm

by 3.5 cm by 3.5 cm and have a density of 0.914 g/ml. How many cubes can he put in the box?
Mathematics
1 answer:
salantis [7]3 years ago
5 0

Answer:

Frank can put 5 cubes in the box.

Step-by-step explanation:

Formula:

Mass = Volume × density.

1 cubic centimetre = 0.001 liter= 1 millilitre

Given that,

Frank purchase a new ice box having 2 kg capacity.

So,the mass of the cubes is 2 kg.

Each ice cubes measured 3.5 cm by 3.5 cm by 3.5 cm.

The volume of a cube is = Side ^3

The volume of a each ice cubes is =3.5^3 cm³

                                                        = 42.875 ml

The ice cubes have a density of 0.914 g/ml

The mass of each cubes are

=volume of each ice cubes × density

=42.875 ml ×0.914 g/ml

=39.18775 gram.

Let x number of ice cubes he can put in the box.

The mass of x cubes is = 39.18775x grams.

2 kg= 2,000 gram [ since 1 kg= 1000 gram]

According to the problem,

39.18775x=2,000

\Rightarrow x=\frac{2000}{39.18775}

\Rightarrow x\approx 51

Frank can put 5 cubes in the box.

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Answer:

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, x^2+4=6x

This can be written as ,  x^2-6x+4=0

We have to solve using quadratic formula,

For a given quadratic equation ax^2+bx+c=0 we can find roots using,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}  ...........(1)

Where,  \sqrt{b^2-4ac} is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}

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Substitute, we get,

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Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

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2 years ago
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