You forgot to include the known characteristics of the solution.
I searched them and copy here:
volume: 1.000 liter
M = 0.0190 M
Now, you can start with the definition of mass percent.
mass percent = (grams of solute / grams of solution) * 100
grams of solute are obtained from the molar concentration:
M = (number of moles of solute) / (volume of solution in liters)
where number of moles = (grams) / (molar mass)
=> M = (grams of solute / molar mass of solute) / (volume of solution in liters)
=> grams of solute = M * (volume of solution in liters) * (molar mass of solute)
And density = (kg of solution / volume of solution in liters) =>
kg of solution = density * volume of solution in liters
grams of solution = density * (volume of solution in liters) * 1000 g/kg
=> mass percent = M * (volume of solution in liters) * (molar mass) / (density * volume of solution in liters * 1000 g/ kg) * 100
=> mass percent = M * molar mass * 10 / density
now replace the values known:
M = 0.0190 mol / liter
density = 1,000 kg / liter
molar mass of Ba(NO3)2 = 137.327 g/mol + 2*14.007 g/mol + 2*3*15.999 g/mol = 256.335 g/mol
=> mass percent = 0.0190 mol/liter * 256.335 g/mol * 10 kg/ g / (1.000 kg/liter)
=> mass percent = 48.7%
Answer:
- HNO3(aq)+NH3(aq)→NH4NO3(aq)+H2O(l): neutralization.
- 2Cu(s)+O2(g)→2CuO(s): redox.
- NaCl(aq)+AgNO3(aq)→NaNO3(aq)+AgCl(s): precipitation.
- 2LiOH(aq)+H2SO4(aq)→Li2SO4(aq)+2H2O(l): neutralization.
- CaCl2(aq)+K2CO3(aq)→2KCl(aq)+CaCO3(s): precipitation.
Explanation:
Hello,
Based on the given reaction and their classification as redox, neutralization or precipitation, one obtains:
- HNO3(aq)+NH3(aq)→NH4NO3(aq)+H2O(l): neutralization as ammonia which is a base, is reacting with nitric acid which is an acid to yield ammonium nitrate which is a base.
- 2Cu(s)+O2(g)→2CuO(s): redox as both copper's and oxygen's oxydation states change by increasing by 2 and reducing by 2 respectively.
- NaCl(aq)+AgNO3(aq)→NaNO3(aq)+AgCl(s): precipitation as the inital reactants are soluble but the yielded silver chloride is not.
- 2LiOH(aq)+H2SO4(aq)→Li2SO4(aq)+2H2O(l): neutralization as lithium hydroxide which is a base reacts with sulfuric acid which is an acid to yield lithium sulfate which is a salt.
- CaCl2(aq)+K2CO3(aq)→2KCl(aq)+CaCO3(s): precipitation since both calcium chloride and potassium carbonate are soluble whereas calcium carbonate is not.
Best regards.
Answer: The reaction rate will INCREASE
Explanation: enzymes are not consumed by the reaction they catalyse, enzyme assay usually follow changes in the concentration of substrate or product to measure the rate of reaction. Now the cys active site contains thiolate ion which will increase on increase of the pk from 8 to 10. Hence increasing the rate of reaction which is catalysed by the active form of the enzyme.
I would think it would be D because if the velocity can change and if that changes then its either acceleration or deceleration. depends on how it changes.
I hope that helps! :)
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