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faust18 [17]
4 years ago
12

a soccer ball is kicked into the air, and it’s path can be modeled with a quadratic function. the table shows the time, t, in se

conds , as the height of the soccer ball,h, in feet
Mathematics
1 answer:
Black_prince [1.1K]4 years ago
4 0

Answer:

f(t)=-2 t(t-5)

-just took the assignment

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Enter the data to create a histogram and use the drop-down menus to complete the statements.
fgiga [73]

Answer:

1.8-9    

2. most often

3.12-13

4.12-13

Step-by-step explanation:

i got it correct thats all i got to say

4 0
3 years ago
Decide whether you would use a permutation, a combination, or neither. Next, write the solution using permutation notation or co
Zepler [3.9K]

Answer:

Permutation is used.

No. of arrangements = 1260

Step-by-step explanation:

Permutation is used for choosing & arrangement of  'r' out of 'n' objects, when sequence is important.

Total no. of alphabets in CORRECT = 7

C is repeated twice, R is repeated twice

So, Total No. of arrangements =   <u>7 !</u>

                                                   (2!)(2!)

= 5040 / 4

= 1260

5 0
3 years ago
What is the equation of the quadratic graph with a focus of (8, −8) and a directrix of y = −6?
yarga [219]
The vertex is exactly half way between directrix and focus. In this case the vertex is (8,-7)
               (h,k)

P is the distance between the vertex and either the directrix or focus,  in this case p = 1. 

a = 1/(4p)  or 1/(4*1) or 1/4

write the equation in vertex form

y = a(x-h)^2 + k

y = 1/4(x-8)^2 -7
4 0
3 years ago
Multiply.
Kamila [148]
Expand the following:
(x - 6) (3 x^2 + 10 x - 1)
Hint: | Multiply out (x - 6) (3 x^2 + 10 x - 1).
 | | | | x | - | 6
 | | 3 x^2 | + | 10 x | - | 1
 | | | | -x | + | 6
 | | 10 x^2 | - | 60 x | + | 0
3 x^3 | - | 18 x^2 | + | 0 x | + | 0
3 x^3 | - | 8 x^2 | - | 61 x | + | 6:
Answer:  3 x^3 - 8 x^2 - 61 x + 6 Thus B:
7 0
3 years ago
The realtor and her clients do not know the average home sale price for all of Guelph (500 was actually just a guess). However,
strojnjashka [21]

Answer:

a) The 99% confidence interval would be given by (346.708;453.292)

b) The 99% confidence interval would be given by (338.445;461.555)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=400 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=80 represent the population standard deviation

n=15 represent the sample size  

2) Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58

Now we have everything in order to replace into formula (1):

400-2.58\frac{80}{\sqrt{15}}=346.708    

400+2.58\frac{80}{\sqrt{15}}=453.292

So on this case the 99% confidence interval would be given by (346.708;453.292)    

3) Part b

For this case we don't know the population deviation so we need to use the t distribution instead the normal standard distribution.

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

We need to find the degrees of freedom first df=n-1=15-1=14

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,14)".And we see that t_{\alpha/2}=2.98

Now we have everything in order to replace into formula (1):

400-2.98\frac{80}{\sqrt{15}}=338.445    

400+2.98\frac{80}{\sqrt{15}}=461.555

So on this case the 99% confidence interval would be given by (338.445;461.555)    

4 0
3 years ago
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