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2 years ago

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Given points A(4, –2), B(1, 2), C(–2, 6). Find the distance between each two of them. Prove that points A, B, and C are collinea

r. Which point is in between the other two? Provide your complete solutions and proofs in your paper homework and enter the numeric answers online.

1 answer:

Alenkasestr [34]2 years ago

7 0

Baldy is on Brainly to smack us AHhHhHh but I don’t know how to solve your problem

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What is the sum of the arithmetic sequence 151, 137, 123,..if there are 26 terms?

ElenaW [278]

First term: a1 = 151
common difference: d = -14 (we decrease by 14 each time, eg, 151-14 = 137)

nth term of this arithmetic sequence is...
an = a1+d(n-1)
an = 151+(-14)(n-1)
an = 151-14n+14
an = -14n+165

This will be used in the formula below

Sn = n*(a1+an)/2
<span>Sn = n*(151+(-14n+165))/2
</span><span>S26 = 26*(151+(-14*26+165))/2 ... replace every n with 26
</span>S26 = -624

The final answer here is choice C) -624
<span>
</span>

5 0

2 years ago

Find the solution of the following equation whose argument is strictly between 270^\circ270 ∘ 270, degree and 360^\circ360 ∘ 360

Natasha2012 [34]

$\rightarrow z^4=-625\\\\\rightarrow z=(-625+0i)^{\frac{1}{4}}\\\\\rightarrow x+iy=(-625+0i)^{\frac{1}{4}}\\\\ x=r \cos A\\\\y=r \sin A\\\\r \cos A=-625\\\\ r \sin A=0\\\\x^2+y^2=625^{2}\\\\r^2=625^{2}\\\\|r|=625\\\\ \tan A=\frac{0}{-625}\\\\ \tan A=0\\\\ A=\pi\\\\\rightarrow z= [625(\cos (2k \pi+pi) +i \sin (2k\pi+ \pi)]^{\frac{1}{4}}\\\\k=0,1,2,3,4,....\\\\\rightarrow z=(625)^{\frac{1}{4}}[\cos \frac{(2k \pi+pi)}{4} +i \sin \frac{(2k\pi+ \pi)}{4}]$

$\rightarrow z_{0}=(625)^{\frac{1}{4}}[\cos \frac{pi}{4} +i \sin \frac{\pi)}{4}]\\\\\rightarrow z_{1}=(625)^{\frac{1}{4}}[\cos \frac{3\pi}{4} +i \sin \frac{3\pi}{4}]\\\\ \rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]\\\\ \rightarrow z_{3}=(625)^{\frac{1}{4}}[\cos \frac{7\pi}{4} +i \sin \frac{7\pi}{4}]$

Argument of Complex number

Z=x+iy , is given by

If, x>0, y>0, Angle lies in first Quadrant.

If, x<0, y>0, Angle lies in Second Quadrant.

If, x<0, y<0, Angle lies in third Quadrant.

If, x>0, y<0, Angle lies in fourth Quadrant.

We have to find those roots among four roots whose argument is between 270° and 360°.So, that root is

$\rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]$

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2 years ago

Find the area of the triangle

Misha Larkins [42]

Answer:

=14.69km²

Step-by-step explanation:

We can use the Hero's formula to calculate the area

A= √(s(s-a)(s-b)(s-c))

s is obtained by adding the lengths of the three sides of the triangle and then dividing by 2, a, b and c are the ides of the triangle.

S=(5+6+7)/2

=9

A=√(9(9-6)(9-5)(9-7))

=√(9×3×4×2)

=√216

=14.69km²

8 0

2 years ago

A family gathered 20 small sea shells from the beach brining the total number of small seashells in their collection to 41.

Novosadov [1.4K]

Answer:

C, x + 20 = 41

Step-by-step explanation:

X represents the number of small sea shells that we originally had. When the family adds 20 more shells, that makes x + 20. The total number is 41, so that means the number of sea shells they already had (x) plus the number of sea shells they collected (20) equals the number of shells they have now (41).

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2 years ago

Let A and B be two events. The probability that event B occurs is 0.72. The probability that events B and A both occur is 0.24.

Sedaia [141]

C is the answer to this question. I hope this helps.

6 0

2 years ago

Read 2 more answers