Answer:
23rd term of the arithmetic sequence is 118.
Step-by-step explanation:
In this question we have been given first term a1 = 8 and 9th term a9 = 48
we have to find the 23rd term of this arithmetic sequence.
Since in an arithmetic sequence

here a = first term
n = number of term
d = common difference
since 9th term a9 = 48
48 = 8 + (9-1)d
8d = 48 - 8 = 40
d = 40/8 = 5
Now 
= 8 + (23 -1)5 = 8 + 22×5 = 8 + 110 = 118
Therefore 23rd term of the sequence is 118.
Answer:
B is correct answer
Step-by-step explanation:
Hope this helps!
Answer: 91 coins
9 x 25 = 2.25 dollars
3 x 10 = 30 cents
1 x 5 = 5 cents
Answer:
Its bus 1 hope it helps goodluck
Answer:

Step-by-step explanation:
*Assuming commas are used for decimals.
<h3><u>Given that:</u></h3>
2.6 kg potatoes = R 13.20
<h3>Using unitary method</h3>
Divide 2.6 to both sides
1 kg potatoes = R 13.20/2.6
1 kg potatoes = R 5.1
Multiply 3.3 to both sides
3.3 kg potatoes = R 5.1 × 3.3
3.3 kg potatoes = R 16.75
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