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Vika [28.1K]
3 years ago
10

What’s the difference between 4 3/5 and 3 5/8 and multiply this by 2 4/9

Mathematics
1 answer:
fenix001 [56]3 years ago
5 0

Answer:

Step-by-step explanation:

2.38333333

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BRAINLIEST IF RIGHT Solve for x <br> -3x-6=16<br> X = -7<br> X = 7.5<br> X = 3<br> X = -4
Troyanec [42]

Answer:

-7

Step-by-step explanation:

3 0
2 years ago
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Add. Simplify the answer and write the answer as a mixed number if appropriate,<br> 4 3 1
denis-greek [22]

Answer:

8

Step-by-step explanation:

4+3=7

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idk if that was what you were looking for please add more information in comments and ill answer

7 0
3 years ago
Newton’s Second Law of Motion states that the acceleration of an object is directly proportional to the force exerted on the obj
aev [14]

The force the same object will exert if it accelerates at a rate of 7 m/s² is 35N

From the question,

We are to determine the force the object will exert.

From the information,

Newton’s Second Law of Motion states that the acceleration of an object is directly proportional to the force exerted on the object

Let acceleration be a

and

Force be F

Then we can write that,

F ∝ a

Then,

Introducing the constant, mass, m

We get

F = ma

Now, we will determine the mass of the object

F = 15 N

a = 3 m/s²

Putting the parameters into the formula, we get

15 = m × 3

∴ m = 15 ÷ 3

m = 5 kg

The mass of the object is 5 kg.

Now, to determine the force the same object will exert if it accelerates at a rate of 7 m/s²

That is,

a = 7 m/s²

and

m = 5 kg

Putting the parameters into the formula, we get

F = 5 × 7

F = 35 N

Hence, the force the same object will exert if it accelerates at a rate of 7 m/s² is 35N

Learn more here: brainly.com/question/13590154

4 0
2 years ago
What is 4,876,213 rounded to the nearest ten thousand
Nutka1998 [239]
4,880,000

hope that helps!!
4 0
3 years ago
Suppose that a, b \in \mathbb{Z}a,b∈Z, not both 00, and let d=\gcd(a, b)d=gcd(a,b). Bezout's theorem states that dd can be writt
lara [203]

Answer:

Step-by-step explanation:

Recall that we say that d | a if there exists an integer k for which a = dk. So, let d = gcd(a,b) and let x, y be integers. Let t = ax+by.

We know that d | a, d | b so there exists integers k,m such that a = kd and b = md. Then,

t = ax+by = (kd)x+(md)y = d(kx+my). Recall that since k,  x, m, y are integers, then (kx+my) is also an integer. This proves that d | t.

3 0
3 years ago
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