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Vika [28.1K]
3 years ago
10

What’s the difference between 4 3/5 and 3 5/8 and multiply this by 2 4/9

Mathematics
1 answer:
fenix001 [56]3 years ago
5 0

Answer:

Step-by-step explanation:

2.38333333

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Please help I cant fail this math test thank you I appreciate it
Marta_Voda [28]

Answer:

d

Step-by-step explanation:

<33

4 0
3 years ago
The angles of a quadrilateral are represented by 9x, (20x + 16) (12x + 10), and (7x- 2)°. What is the value of x?
Pepsi [2]

Answer:

x=7

Step-by-step explanation:

9x+20x+16+12x+10+7x-2=360

48x+24=360

48x=360-24

48 x=336

x=336/48=7

5 0
3 years ago
Can someone please explain The measure of angle A to the nearest tenth of a degree is:
Ratling [72]

Answer:

A =19.5

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin A= opp/ hyp

sin A = 3/9

Take the inverse sin of each side

sin ^-1 sin A = sin ^-1 (3/9)

A =19.47122063

To the nearest  tenth of a degree

A =19.5

3 0
3 years ago
Read 2 more answers
Uninhibited growth can be modeled by exponential functions other than​ A(t) ​=Upper A 0 e Superscript kt. For ​ example, if an i
laila [671]

The question is incomplete. Here is the complete question.

Uninhibited growth can be modeled by exponential functions other than A(t)=A_{0}e^{kt}. for example, if an initial population P₀ requires n units of time to triple, then the function P(t)=P_{0}(3)^{\frac{t}{n} } models the size of the population at time t. An insect population grows exponentially. Complete the parts a through d below.

a) If the population triples in 30 days, and 50 insects are present initially, write an exponential function of the form P(t)=P_{0}(3)^{\frac{t}{n} } that models the population.

b) What will the population be in 47 days?

c) When wil the population reach 750?

d) Express the model from part (a) in the form A(t)=A_{0}e^{kt}.

Answer: a) P(t)=50(3)^{\frac{t}{30} }

              b) P(t) = 280 insects

              c) t = 74 days

             d) A(t)=50e^{0.037t}

Step-by-step explanation:

a) n is time necessary to triple the population of insects, i.e., n = 30 and P₀ = 50. So, Exponential equation for growth is

P(t)=50(3)^{\frac{t}{30} }

b) In t = 47 days:

P(t)=50(3)^{\frac{t}{30} }

P(47)=50(3)^{\frac{47}{30} }

P(47)=50(3)^{1.567}

P(47) = 280

In 47 days, population of insects will be 280

c) P(t) = 750

750=50(3)^{\frac{t}{30} }

\frac{750}{50}=(3)^{\frac{t}{30} }

(3)^{\frac{t}{n} }=15

Using the property <u>Power</u> <u>Rule</u> of logarithm:

log(3)^{\frac{t}{30} }=log15

\frac{t}{30}log(3)=log15

t=\frac{log15}{log3} .30

t = 74

To reach a population of 750 insects, it will take 74 days

d) To express the population growth into the described form, determine the constant k, using the following:

A(t) = 3A₀ and t = 30

A(t)=A_{0}e^{kt}

3A_{0}=A_{0}e^{30k}

3=e^{30k}

Use Power Rule again:

ln3=ln(e^{30k})

ln3=30k

k=\frac{ln3}{30}

k = 0.037

Equation for exponential growth will be:

A(t)=50e^{0.037t}

3 0
3 years ago
An audio cable is 15.9 dm long. How long is the cable in meters?
sveta [45]

1.59 meters is the correct answer i think.

3 0
3 years ago
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