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Leona [35]
3 years ago
15

What is AE ? Enter your answer in the box. units Two segments A D and B C intersect at point E to form two triangles A B E and D

C E. Side A B is parallel to side D C. A E is labeled 2 x plus 10. E D is labeled x plus 3. A B is 10 units long. D C is 4 units long

Mathematics
1 answer:
spin [16.1K]3 years ago
5 0

Answer:

The length of AE is 20 units.

Step-by-step explanation:

Given two segments AD and BC intersect at point E to form two triangles ABE and DCE. Side AB is parallel to side DC. A E is labeled 2x+10. ED is labeled x+3. AB is 10 units long and DC is 4 units long.

we have to find the length of AE

AB||CD ⇒ ∠EAB=∠EDC and ∠EBA=∠ECD  

In ΔABE and ΔDCE

∠EAB=∠EDC      (∵Alternate angles)

∠EBA=∠ECD      (∵Alternate angles)

By AA similarity, ΔABE ≈ ΔDCE

therefore, \frac{AE}{ED}=\frac{AB}{CD}

⇒ \frac{2x+10}{x+3}=\frac{10}{4}

⇒ 8x+40=10x+30

⇒ x=5

Hence, AE=2x+10=2(5)+10=20 units

The length of AE is 20 units.

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Find the distance between points A (10,-1) and B (-2,5). Round to the nearest tenth
bija089 [108]

Answer:

<h2>The answer is 13.4 units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2}  +  ({y1 - y2})^{2} }  \\

where

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From the question the points are

A (10,-1) and B (-2,5)

The distance is

|AB|  =  \sqrt{ ({10 + 2})^{2} +  ({ - 1 - 5})^{2}  }  \\  =  \sqrt{ {12}^{2}  +  ({ - 6})^{2} }  \\  =  \sqrt{144 + 36}  \:  \:  \:  \:  \:  \:  \:   \\  =  \sqrt{180}  \\  = 6 \sqrt{5}  \:  \:  \\  =13.416407

We have the final answer as

<h3>13.4 units to the nearest tenth</h3>

Hope this helps you

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