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DedPeter [7]
3 years ago
5

What is the length of ST¯¯¯¯¯? Enter your answer as a decimal in the box. Round your final answer to the nearest hundredth. in.

Circle A with a tangent and a secant segment. Point S at 11 o clock, point R at 2 o clock, and point Q at 6 o clock are located on the circle. Point T at 2 o clock is located outside of the circle. Tangent S T and secant Q R T is drawn that intersect each other at point T. Segment R T is labeled as 7 inches. Segment R Q is labeled as 23 inches.

Mathematics
2 answers:
allochka39001 [22]3 years ago
8 0

Answer:

_ST = TQ-TR (23-7)

Yanka [14]3 years ago
6 0

Answer:

16 in.

Step-by-step explanation:

23-7=16 hence you cane see that the angles are 16 inches.

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Find the indicated length or angle measure (to the nearest tenth).
skad [1K]

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Explain the formula to use

Using the cosine rule which states that:

z^2=x^2+y^2-2xy\cos Z

STEP 2: Write the given sides

x=4,y=6,Z=41^{\circ},z=?

STEP 3: Find the value of z

\begin{gathered} By\text{ substitution,} \\ z^2=4^2+6^2-2(4)(6)\cos41 \\ z^2=16+36-48cos41 \\ z^2=52-36.22605985 \\ z^2=15.77394015 \\ z=\sqrt{15.77394015} \\ z=3.971641997 \\ z\approx4.0 \end{gathered}

Hence, the indicated length is 4.0

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1 year ago
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Here are two rectangular prisms:
Leno4ka [110]

Answer:

hey there buddy

Step-by-step explanation:

3 0
3 years ago
On a coordinate plane, 2 triangles are shown. The first triangle has points S (3, 5), R (5, 0), and Q (1, 0). The second triangl
enyata [817]

Answer:

<u>B. (x, y) → (–x, –y).</u>

Step-by-step explanation: This is the correct answer on <u>Edge 2021</u>, just did the assignment. Hope this helps ^-^.

6 0
3 years ago
QUESTION 1
Kitty [74]

It's difficult to make out what the force and displacement vectors are supposed to be, so I'll generalize.

Let <em>θ</em> be the angle between the force vector <em>F</em> and the displacement vector <em>r</em>. The work <em>W</em> done by <em>F</em> in the direction of <em>r</em> is

<em>W</em> = <em>F</em> • <em>r</em> cos(<em>θ</em>)

The cosine of the angle between the vectors can be obtained from the dot product identity,

<em>a</em> • <em>b</em> = ||<em>a</em>|| ||<em>b</em>|| cos(<em>θ</em>)   ==>   cos(<em>θ</em>) = (<em>a</em> • <em>b</em>) / (||<em>a</em>|| ||<em>b</em>||)

so that

<em>W</em> = (<em>F</em> • <em>r</em>)² / (||<em>F</em>|| ||<em>r</em>||)

For instance, if <em>F</em> = 3<em>i</em> + <em>j</em> + <em>k</em> and <em>r</em> = 7<em>i</em> - 7<em>j</em> - <em>k</em> (which is my closest guess to the given vectors' components), then the work done by <em>F</em> along <em>r</em> is

<em>W</em> = ((3<em>i</em> + <em>j</em> + <em>k</em>) • (7<em>i</em> - 7<em>j</em> - <em>k</em>))² / (√(3² + 1² + 1²) √(7² + (-7)² + (-1)²))

==>   <em>W</em> ≈ 5.12 J

(assuming <em>F</em> and <em>r</em> are measured in Newtons (N) and meters (m), respectively).

3 0
3 years ago
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