We know that 70 sixth graders had an average weight of 90 pounds, and 30 seventh graders had an average weight of 100 pounds.
We know that the weight of all 70 sixth graders will be 70*90, since we're multiplying the total amount of students by the average.
Using this same logic tells us that the total weight for the 30 seventh graders is 30*100
The average weight for all 100 students will be the total weight of the sixth graders (which is 70*90) added with the total weight of the seventh graders (which is 30*100), then finally divided by the total amount of students in the sample space (which is 100).
The average of all 100 students is 93 pounds.
Let me know if you need any clarifications, thanks!
Answer:
Step-by-step explanation:
The trick here (and it is tricky!) is to find the area of the parallelogram as a whole based on the information you're given, and then use that area to solve for h. If we look at the parallelogram sideways and use 5.5 as the height, the base is 9.9. The area for a parallelogram is A = bh, so A = 9.9(5.5) so
A = 54.45 in squared. Now we will use that area value along with the height of h and the base of 11. Remember, just because we are using different numbers this time, the area of the parallelogram doesn't change. Therefore,
54.45 = 11(h) and
h = 4.95 in.
If a, b, c is an arithmetic sequence then a + c = 2b
a = 5, b = 9, c = 15
subtitute
a + c = 5 + 15 = 20
2b = 2 · 9 = 18
20 ≠ 18
Answer: The sequence 5, 9, 15 is not an arithmetic sequence.
Answer:
a
Step-by-step explanation:
the volume of a square pyramid is V=1/3bxh
2) Corresponding angles of parallel lines cut by a transversal are congruent.
3) Vertical angles are congruent.
4) Transitive Property. If angle 2 is congruent to angle 6 and angle 4 is congruent to 2, then angle 6 is congruent to angle 4.
