What all chances are there? If there are no other options then 100.
(2x+3)(2x+3) is the answer. Multiply contents of brackets on each other so, 4x+6x+6x+9=4x^2+12x+9
This is a rectangle, meaning that all angles are right angles and all sides opposite to one another have equal length.
Since the length of CD is 24, the length of AB must also be 24.
Angle B is a right angle because this is a rectangle.
See anything? I'll you a hint. We have a right triangle with only one missing value.
What do we use to solve for missing lengths in a right triangle? The Pythagorean theorem, of course!

The length of c (the hypotenuse) is 26.
The length of a (one leg) is 24.
The length of b is unknown and we want to find it.


Subtract 576 by both sides.

Take square root of both sides.

The length of the missing leg is 10, meaning that the length of BD is 10.
This is what you should be needing. Enjoy!
Answer:
First question, x= 10^10.
Second question is 10!. or 362880
Step-by-step explanation:
First Question:
Simple logx has a base of 10, i.e log10 x,
the question will be 10 = log10 x,
when taking the base "10" from the right side to the left, the number on the left side becomes the power of the base, in this case 10 from the right will be base and 10 from the left will power and log will vanish.
x=10^10.
Another example with different numbers
Y=logx if Y= 12, What is x?
The base is ten when not given,so:
12=logx
10^12=x
Second Question;
simple multiplication just multiply the numbers.
10! is pronounced as 10 factorial,
5! will be 5x4x3x2x1=120
Answer:
−2 is a member of the domain of f.
f(0) > 0
Step-by-step explanation:
Statement 1 is TRUE. Domain value includes set of values of x of the function. -2 is plotted on the x-axis on the graph. Therefore, it is a member of domain of f.
Statement 2 is incorrect. Range includes all possible y-values of the function. On the graph, no y-value plotted is -2. Therefore, -2 is NOT a member of the range of f.
Statement 3 is TRUE.
f(0) is approximately 2.2 on the graph. i.e. at x = 0, y ≈ 2.2.
Therefore, f(0) > 0.
Statement 4 is INCORRECT.
f(2) = 1, that is at x = 2, y = 1 as seen in the graph. Therefore, f(2) is not greater than 2.