Hope this helps. Domain and range are the same for this question.
Answer:
1.1
Step-by-step explanation:
Answer:
Step-by-step explanation:
We that the area of a circle is Pi times r^2 where r is the radius
Let A be the area of the first circle and S the area of the second one and T the total one
A=4^2× Pi
S=6^2× Pi
T = Pi( 4^2 +6^2)
= Pi ( 16+36) = Pi× 52
52 is the radius square
So r = root square 52 = 2 root square 13
3n=15-(6/3)
3n=15-2
3n=13
n=(13/3)
