All categories

3 years ago

Use the given graph to determine the limit, if it exists.

Mathematics

1 answer:

Contact [7]3 years ago

4 0

The limit as x approaches 3 from the left is observed based on the upward sloping line. If we observe beginning from x = 2 to x = 2.5 to x = 2.9, drawing closer to 3, we can see that it approaches the point (3, 1), so the limit is the y-value of 1.

The point at (3,1) being hollow does not matter, since we are only asking for the limit as x approaches 3, not the value at x = 3.

You might be interested in

Draw a scale diagram of 15 mm scale factor of 8 <br><br> pleaseee help

trapecia [35]

do u want us to draw it 4 u ? cuz I can

8 0

3 years ago

A local club organizes a festival with an entry fee of $6. At the festival, bags of popcorn cost $4 each. Which expression can b

11Alexandr11 [23.1K]

6x + 4x

Hope this helps :)

8 0

3 years ago

Pls, help. Whichever one you want, but whoever does all of them first I will give them the brainiest.

Nana76 [90]

1. -37b-1
2. X=24
3. Z=18.
Hope this helps!

5 0

3 years ago

A teacher wants to give 3 markers to

Novay_Z [31]

First, find out how many markers in total the teacher will need.
$25*3=75$
Then, find out how many packages the teacher will need by dividing by 8 because that's how many are in each package.
$\frac{75}{8}=9.375$
Now because there is a remainder of .375 that tells us that there are not enough markers in 9 packages to give all students 3 each.

She will have to buy an additional package to give every student 3 markers each.

10 Packages are needed.

8 0

3 years ago

Read 2 more answers

I need help this question?

Masja [62]

Answer:

Correct answer: F. graph F or x ∈ |-5 ; 5| (including endpoints)

Step-by-step explanation:

Let us first define the absolute value:

| x | = 1. { x with condition x ≥ 0 }

or 2. { - x with condition x < 0 }

This is a linear inequality

1. x ≤ 5 ∧ x ≥ 0 ⇒ 0 ≤ x ≤ 5 or interval x ∈ |0 ; 5| (including endpoints)

2. - x ≤ 5 when we multiply both sides of the equation by -1 we get:

x ≥ -5 ∧ x < 0 ⇒ -5 ≤ x < 0 or interval x ∈ |-5 ; 0) (including -5)

The solution to this linear inequality is the union of these two intervals:

x ∈ |-5 ; 0) ∪ |0 ; 5| ⇒ x ∈ |-5 ; 5| (including endpoints)

x ∈ |-5 ; 5| (including endpoints)

God is with you!!!

7 0

4 years ago