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Serggg [28]
3 years ago
8

There are 3 consecutive integers that add up to 9 which integers are they?

Mathematics
1 answer:
matrenka [14]3 years ago
7 0

Answer:

The integers are 2,3,4

Step-by-step explanation:

Let one integer be = x

Since, the integers are consecutive, so they will increase by one.

So, 2nd integer will be =x+1

3rd integer will be =x+1+1=x+2

It is given that the 3 integers add up to 9.

So, we have the sum equation as:

x+x+1+x+2=9

Solving for x

Combining like terms.

3x+3=9

Subtracting both sides by 3.

3x+3-3=9-3

3x=6

Dividing both sides by 3.

\frac{3x}{3}=\frac{6}{3}

x=2

∴ 1st integer = 2

2nd integer = 2+1 = 3

3rd integer = 2+2 = 4

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Use the following image to assist in your answer.<br> a =<br> - 6<br> - 9<br> - 4
vfiekz [6]

Step-by-step explanation:

Pythagoras' theorem for the smallest one :

c^2 = 4^2 + 6^2

c^2 = 16 + 36

c^{2} = 52

Pythagoras' theorem for the middle one :

b^{2} = 6^{2} + a^{2}

Pythagoras' theorem for the biggest one :

(4+a)^2 = c^2 + b^2

16 + 8a + a^2 = 52 + b^2

Using the formula before (for b^2) it becomes :

16 + 8a + a^2 = 52 + (6^2 + a^2)

16 + 8a + a^2 = 52 + 6^2 + a^2

16 + 8a = 52 + 6^2

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a = \frac{72}{8}

a = 9

Verifying :

b^2 = 6^2 + a^2

b^2 = 36 + 81

b^2 = 117

b^{2} = 117

The biggest one :

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True

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