Answer:
In a fruit fly experiment, grey body, normal winged (homozygous dominant) fruit flies were mated with black body, short winged (homozygous recessive) fruit flies. The F1 dihybrid females were then used in a test cross. If the genes are always linked and no crossing over occurs, what would be the predicted ratio in the F2 generation?
GG x bb = Gb, Gb, Gb and Gb F1 generation
grey body heterozygous offspring 4:0
Gb x Gb= GG, Gb, Gb, and bb F2 generation
3:1 three grey body fly and one black body fly
Explanation:
Answer:
The correct answer is "Shine Dalgarno sequence".
Explanation:
- A consensus originally characterized throughout the mRNAs to Escherichia coli seems to be the Shine-Dalgarno chain.
- Proteins manufactured through sequences comprising unique sequences became generated more gradually or slowly than similar proteins encoded of separate but interchangeable codons from genes, researchers observed.
Oranelles carry out specific functions within the cell
It should be 3! That is the only logical answer to the question...
Complete question:
You will find the complete question in the attached files, due to technical problems
Answer:
This conclusion is incorrect. Only half of the progeny will have a dominant and a recessive allele, Aa. The other half will carry two dominant alleles, AA.
Explanation:
Due to technical problems, you will find the complete explanation in the attached files.