Answer:
Phenotypic changes:
When Rhodobacter is cultured in total darkness for multiple generations, the ability to produce it's own photopigment reduces with time with little or no ability to undergo its own photosynthesis due to absence of enzymes or pigment for photosynthesis.
It becomes expensive for the Rhodobacter to undergo photosynthesis. This allows mutants that can grow in the dark to take over from the culture grown in the dark.
Evolutionary processes:
It's natural selection that allows the fittest organism to survive. As in the case of the mutants
Answer:
Sensory neurons. Sensory neurons help you: ...
Motor neurons. Motor neurons play a role in movement, including voluntary and involuntary movements. ...
Interneurons.
Explanation:
<span>D) possibility that native wild organisms could overpower the cloned organisms, causing them to become extinct
Whenever you do bioengineering, you want to affect the existing ecosystems as little as possible.</span>
<h3><u>Answer</u>;</h3>
An increase in the total biomass of consumers in the world
<h3><u>Explanation</u>;</h3>
- Carbon fixation is the process through which carbon dioxide is removed from the air and incorporated into an organic molecule.
- Carbon fixation occurs during the light independent reaction of photosynthesis and is the first step in the C3 or Calvin Cycle.
- The Calvin cycle uses the energy from short-lived electronically excited carriers to convert carbon dioxide and water into organic compounds that can be used by the organism.
The question is incomplete and the complete question is
Suppose that ear length in rabbits is controlled by two additive genes, each of which has two alleles. A true-breeding female (aabb) with 6-cm ears is mated to a true-breeding male (AABB) with 16-cm ears.
Answer:
AABb or AaBB
Explanation:
We know that,
aabb genotype - 6 cm
AABB genotype- 16-cm
To calculate the length of earlobe contributed by each allele in a genotype is :
1. length of aabb/4 or 6/4= 1.5 cm (a and b contribute for 1.5 cm each)
2. Length of AABB/4 or 16/4= 4 cm (A and B contribute for 4 cm each)
Now to have the earlobe to be 13.5 cm long then the genotype must be
13.5 = 4+4+4+1.5 or A+A+B+b or A+a+B+B
Therefore, the genotype will be-either AABb or AaBB
