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Hoochie [10]
3 years ago
9

Use the scale and map measurements to find the actual distance from New Wilmington to Sharon through Mercer. What is the actual

distance if you travel from New Wilmington to Sharon through Volant?
51 mi; 45 mi

102 mi; 90 mi

76.5 mi; 67.5 mi

25.5 mi; 22.5 mi

Mathematics
2 answers:
Fynjy0 [20]3 years ago
8 0
Your answer is C!

Hope i helped!
  

~Cakes



irga5000 [103]3 years ago
6 0

Answer:

Option A. 51miles, 45 miles

Step-by-step explanation:

Distance between New Wellington to Sharon through Mercer is given as

Distance between New Wellington to Mercer + Distance between Mercer to Sharon

= 2 + 2.25

= 4.25 in.

Now we have been given the conversion formula as

1 in = 12 miles

So 4.25 in. will be = 12×4.25 miles

                              = 51 miles

Therefore, actual distance from New Wilmington to Sharon via Mercer is 51 miles.

Now we have to calculate the actual distance between New Wilmington to Sharon through Volant.

Distance between New Wilmington to Volant = 1 in.

and distance between Volant to Sharon = 2.75 in.

Distance between New Wilmington to Sharon via Sharon = 2.75 + 1 = 3.75 in.

Now we will use conversion table to get the actual distance.

∵ 1 in. distance = 12 miles

∴ 3.75 in distance = 12×3.75 = 45 miles

Therefore, Option A. 51 miles and 45 miles is the answer.

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Need help with this thanks
lorasvet [3.4K]

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126/420

Step-by-step explanation:

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5 0
3 years ago
Pls help me solve this questionnnnn
BigorU [14]

9514 1404 393

Answer:

  • arc BC = 60°
  • m∠ADC = 60°
  • m∠AEB = 105°
  • m∠ADP = 45°
  • m∠P = 60°

Step-by-step explanation:

The sum of arcs of a circle is 360°. The given conditions tell us arc BC ≅ arc AB, so the four arcs of the circle have ratios ...

  CB : BA : AD : DC = 2 : 2 : 3 : 5

The sum of ratio units is 2+2+3+5 = 12, so each one stands for 360°/12 = 30°. Then the arc lengths are ...

  arc BC = arc BA = 60° . . . . 2 ratio units each

  arc AD = 90° . . . . . . . . . . . . 3 ratio units

  arc DC = 150° . . . . . . . . . . . .5 ratio units

The inscribed angles are half the measure of the intercepted arcs:

  ∠ADC = (1/2) arc AC = 1/2(120°) = 60°

  ∠ADP = 1/2 arc AD = 1/2(90°) = 45°

The angles at E are half the sum of the measures of the intercepted arcs.

  ∠AEB = (arc AB + arc CD)/2 = (60° +150°)/2 = 105°

Angle P is half the difference of the intercepted arcs.

  ∠P = (arc BD -arc AD)/2 = (210° -90°)/2 = 120°/2 = 60°

__

In summary, ...

  arc BC = 60°

  m∠ADC = 60°

  m∠AEB = 105°

  m∠ADP = 45°

  m∠P = 60°

6 0
3 years ago
HELP GIVING CROWN IF ANSWERED RIGHT!!!!!
olganol [36]
If my math is right it should be B)
8 0
3 years ago
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