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I am Lyosha [343]
3 years ago
6

-2 5/9 × 1 1/8 I dont know how to show work​

Mathematics
2 answers:
olchik [2.2K]3 years ago
6 0

Answer:

-13/8

Step-by-step explanation:

1) Multiply -2 times the denominator (9) and add it to the numerator (5)

-13/9 x 1 1/8

2) Multiply 1 times the denominator (8) and add it to the numerator (1) like before

-13/9 x 9/8

3) Multiply the two fractions (but simplify the nines first!)

-13/1 x 1/8 = -13/8

dezoksy [38]3 years ago
3 0

Answer:

Step-by-step explanation:

-2 5/9 = (-2 * 9 - 5)/9 = -23/9

1 1/8 =  9/8

Product = -23/9 * 9/8

Product = -23/8 or

Product = -2.875 or

Product = -2 7/8

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Tanya [424]
In decimal 11/40= 0.275
4 0
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Multiply the following expressions<br> 81x5y6 × (-1x2y)​
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Answer: -4860y^2

Solution:
81 x (5y x 6) x (-2y)
-81 x 5y x 6 x 2y
= -4860y^2
5 0
2 years ago
You plan to construct a brick wall measuring 14.5 ft. in length, 5.5 ft. high, and 0.5 ft. in width. If a brick measures 6 in. x
Kobotan [32]

14.5 x 5.5x 0.5 = 39.875 cubic feet for the wall

 brick = .5 x .333 x 0.167 = 0.0278 cubic feet rounded to 0.03

39.875/0.03 = 1329.16

so approximately 1330 bricks are required.


 This could be a little different depending on how you round everything off



4 0
4 years ago
Read 2 more answers
Tomas ran a Lucky Dip stall.
oksian1 [2.3K]

Answer:

637

Step-by-step explanation:

Ticket ending 00= £12 * 7 = £84  

Tickets ending 5 = £1.5 * 75 = £112.5  

£84+£112.5=£196.5  

Price money + Profit: £196.5+£163= 356

356/£0.5 = 719 total tickets sold

719- 82 (WINNING TICKETS) = 637 losing tickets sold

3 0
3 years ago
The weights of cockroaches living in a typical college dormitory are approximately distributed with a mean of 80 grams and a sta
Romashka [77]

Answer:

The percentage of cockroaches weighing between 77 grams and 83 grams is about 55%.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 80, \sigma = 4

The percentage of cockroaches weighing between 77 grams and 83 grams

This is the pvalue of Z when X = 83 subtracted by the pvalue of Z when X = 83. So

X = 83

Z = \frac{X - \mu}{\sigma}

Z = \frac{83 - 80}{4}

Z = 0.75

Z = 0.75 has a pvalue of 0.7734

X = 77

Z = \frac{X - \mu}{\sigma}

Z = \frac{77 - 80}{4}

Z = -0.75

Z = -0.75 has a pvalue of 0.2266

0.7734 - 0.2266 = 0.5468

Rounded to the nearest whole number, 55%

The percentage of cockroaches weighing between 77 grams and 83 grams is about 55%.

7 0
4 years ago
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