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iren [92.7K]
3 years ago
6

If you wanted to shift the graph of y=4x+7 down , which equation could you use ?

Mathematics
2 answers:
BaLLatris [955]3 years ago
7 0

Answer:

y=4x+3

Step-by-step explanation:

shtirl [24]3 years ago
4 0
Well, the function is written in y = mx + b, which is slope intercept form.  If the graph were to shift down, you would reduce "b" by the number of units that you want to shift.

Therefore for the specific question you posted, and assuming your shift is "k" units - the equation would be ---

y = 4x + (b + k)
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Pls help <br><br> Thank you ❤️
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Answer:

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Step-by-step explanation:

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4 0
3 years ago
7.5 x 7.5 x (6.084−5.44)
Mars2501 [29]

Hello!

Answer:

36.225

Step-by-step explanation:

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8 0
3 years ago
Square of a binomial x^2+2x+1
garik1379 [7]
To put an equation into (x+c)^2, we need to see if the trinomial is a perfect square. 
General form of a trinomial: ax^2+bx+c
If c is a perfect square, for example (1)^2=1, 2^2=4, that's a good indicator that it's a perfect square trinomial. 
Here, it is, because 1 is a perfect square.
To ensure that it's a perfect square trinomial, let's look at b, which in this case is 2. 
It has to be double what c is.
2 is the double of 1, therefore this is a perfect square trinomial. 
Knowing this, we can easily put it into the form (x+c)^2.
And the answer is: (x+1)^2.
To do it the long way:
x^2+2x+1
Find 2 numbers that add to 2 and multiply to 1. 
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x^2+x+x+1
x(x+1)+1(x+1)
Gather like terms
(x+1)(x+1)
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3 0
3 years ago
A sphere and a cylinder have the same radius and height. The volume of the cylinder is 8 meters cubed. Yolanda found the volume
LenKa [72]

Answer:

Yolanda should have found the volume by multiplying 8 by 2/3.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Please answer correctly !!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!!
il63 [147K]

Answer:

x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

Step-by-step explanation:

w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

6 0
3 years ago
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