Answer:
They are all equal and identical in form; coinciding exactly when superimposed.
Step-by-step explanation:
since LM=LN there values are same which is given as 5.5 cm and MN =7cm
now draw a line LM which is 5.5 cm long. From one point of this line construct an arc 5.5 cm in upward direction.Then from the opposite end of the same line LM construct an arc 7 cm long in upward direction. Let it meet the the first arc at any point. The arcs will meet for sure at any angle. Join the two ends of line LN to this point where they meet. We get a triangle!
Remember to mark LM , LN and MN as soon as u draw them so as to avoid confusion.
<em>IF U WANT I'LL DO IT AND SEND A PHOTO</em>
Answer:
S(3)=22
Step-by-step explanation:
The rate of change of the number of squirrels S(t) that live on the Lehman College campus is directly proportional to 30 − S(t).


When t=0, S(t)=15

When t = 2, S(t)=20

Therefore:

One.
To find the area of a 3D object you multiply length, width, and hight.
So 1 x 1 x 1 = 1